一、概述
有一个django项目，由于业务要求，自己构造了一个list数据类型。这是一个临时数据，不需要保存到表中，但是需要分页展示。
由于之前学习的Django的分页器(paginator)，参考链接：
https://www.cnblogs.com/xiao987334176/p/9285629.html
它是针对于queryset类型做的分页，那么list类型是否也可以呢？答案是可以的！
二、项目测试
新建项目paging_demo
本文使用的django版本为2.x系列
paging_demo/urls.py
from django.contrib import admin from django.urls import path from application import views urlpatterns = [ path('admin/', admin.site.urls), path('', views.index), ]
paging_demo/settings.py ，最后一行增加
# 每一页显示几条 PAGE_SIZE = 10 # 分页数 PAGE_NUM_PAGES = 11
application/views.py
from django.shortcuts import render from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger from paging_demo import settings # Create your views here. def index(request): """ 首页 :param request: :return: """ host_list = [] for i in range(100): dic = {"id":i,"ip":"192.168.1.%s"%i} host_list.append(dic) # 分页 paginator = Paginator(host_list, settings.PAGE_SIZE) # 每页显示指定的条数 # 异常判断 try: # 当前页码，如果取不到page参数，默认为1 current_num = int(request.GET.get("page", 1)) # 当前页码 host_list = paginator.page(current_num) # 获取当前页码的数据 except EmptyPage: # 页码不存在时,报EmptyPage错误 log_list = paginator.page(1) # 强制更新为第一页 # 如果页数十分多时，换另外一种显示方式 if paginator.num_pages > settings.PAGE_NUM_PAGES: # 一般网页展示11页,左5页,右5页,加上当前页,共11页 if current_num - 5 < 1: # 如果前5页小于1时 pageRange = range(1, settings.PAGE_NUM_PAGES) # 页码的列表:范围是初始状态 elif current_num + 5 > paginator.num_pages: # 如果后5页大于总页数时 # 页码的列表:范围是(当前页-5,总页数+1)。因为range顾头不顾尾,需要加1 pageRange = range(current_num - 5, paginator.num_pages + 1) else: # 页码的列表:后5页正常时,页码范围是(当前页-5,当前页+6)。注意不是+5,因为range顾头不顾尾！ pageRange = range(current_num - 5, current_num + 6) else: pageRange = paginator.page_range # 页码的列表 data = { "paginator": paginator, "current_num": current_num, "pageRange": pageRange, "host_list": host_list } return render(request, "index.html", data)
templates/index.html
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Title</title> <link href="https://cdn.bootcss.com/twitter-bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet"> <script src="https://cdn.bootcss.com/jquery/3.4.1/jquery.min.js"></script> </head> <body> <div class="container"> <div class="row"> <div class="panel panel-success"> <!-- Default panel contents --> <div class="panel-heading text-center"> <span>主机列表</span> </div> <!-- Table --> <table class="table table-bordered"> <thead> <tr> <th>序号</th> <th>ip地址</th> {# <th>操作</th>#} </tr> </thead> <tbody> {% for item in host_list %} <tr> <th> <span>{{ forloop.counter }}</span> </th> <td>{{ item.ip }}</td> </tr> {% endfor %} </tbody> </table> </div> {#分页展示#} <nav aria-label="Page navigation"> <ul class="pagination"> <li><a href="?page=1" aria-label="Previous"><span aria-hidden="true">首页</span></a></li> {#has_previous 判断是否有上一页#} {% if host_list.has_previous %} {#previous_page_number 上一页的页码#} <li><a href="?page={{ host_list.previous_page_number }}" aria-label="Previous"><span aria-hidden="true">上一页</span></a></li> {% else %} {#class="disabled" 禁止用户点击#} <li class="disabled"><a href="" aria-label="Previous"><span aria-hidden="true">上一页</span></a></li> {% endif %} {#遍历页码的列表#} {% for i in pageRange %} {#判断当前页码数等于底部页码时#} {% if current_num == i %} {#增加class,加深按钮#} <li class="active"><a href="?page={{ i }}">{{ i }}</a></li> {% else %} {#href参数为简写,它会自动获取当前路径，并拼接参数#} <li><a href="?page={{ i }}">{{ i }}</a></li> {% endif %} {% endfor %} {#has_next 判断是否有下一页#} {% if host_list.has_next %} {#next_page_number 下一页的页码#} <li><a href="?page={{ host_list.next_page_number }}" aria-label="Next"><span aria-hidden="true">下一页</span></a></li> {% else %} {#class="disabled" 禁止用户点击#} <li class="disabled"><a href="" aria-label="Next"><span aria-hidden="true">下一页</span></a></li> {% endif %} <li><a href="?page={{ paginator.num_pages }}" aria-label="Next"><span aria-hidden="true">最后一页</span></a> </li> </ul> </nav> </div> </div> </body> </html>
运行项目，访问页面：
http://127.0.0.1:8000/
效果如下：
