zoukankan      html  css  js  c++  java
  • 9.积分和微分运算

    概述:

    1  定积分概念

    2  利用梯形求面积

    1 clear all;
    2 X1=[1 2 3 4 5 6 7]
    3 z1=trapz(X1)
    4 X2=[1 2 3;3 6 8;2 5 9]
    5 z2=trapz(X2)
    6 z3=trapz(X2,2)
    7 x=[1 2 3]
    8 z4=trapz(x,X2)

    3  利用矩形求面积

    1 clear all;
    2 X1=[1 2 3 4 5 6 7]
    3 z1=cumsum(X1)
    4 X2=[1 2 3;3 6 8;2 5 9]
    5 z2=cumsum(X2)
    6 z3=cumsum(X2,1)
    7 z4=cumsum(X2,2)
    8 z5=cumsum(X2,3)
     1 clear all;
     2 x=0:0.01:5*pi;
     3 y=cos(x./2)';
     4 z=cumsum(y)*0.01;
     5 z1=z(end)
     6 z2=trapz(x,y)
     7 figure;
     8 plot(x,y,'r-');
     9 hold on;
    10 plot(x,z,'b:')
    11 legend('被积函数','积分曲线'); 

    4  单变量数值积分求解

    1 function y=myfun1(x)
    2 y=1./(sin(x)+exp(-x.^2));
    1 clear all;
    2 syms x;
    3 f=inline('1./(sin(x)+exp(-x.^2))')
    4 y=quad(f,0,1.3)
    5 y1=quad(@myfun1,0,1.3)
    6 y2=quad(@myfun1,0,1.3,1.e-10)
    1 clear all;
    2 syms x;
    3 f=inline('1./(sin(x)+exp(-x.^2))','x');
    4 y=quadl(f,0,1.3)
    5 y1=quadl(f,0,1.3,1.e-20)

    5  双重积分求解

     

    1 function z= integrnd(x,y)
    2 z=y*sin(x)+x*cos(y);
    1 clear all;
    2 syms x;
    3 f=inline('x*cos(y)+y*sin(x)','x','y');
    4 y=dblquad(f,pi,2*pi,0,pi)
    5 y1=dblquad(@integrnd,pi,2*pi,0,pi)
    6 y2=dblquad(@(x,y) x*cos(y)+y*sin(x),pi,2*pi,0,pi)

    6  三重积分求解

    1 clear all;
    2 f=inline('z*cos(x)+y*sin(x)','x','y','z');
    3 q=triplequad(f,0,pi,0,1,-1,1)
    4 %采用匿名函数的形式
    5 q1=triplequad(@(x,y,z) (y*sin(x)+z*cos(x)),0,pi,0,1,-1,1)
    6 q2=triplequad(@(x,y,z) (y*sin(x)+z*cos(x)),0,pi,0,1,-1,1,1.e-10)
    7 q3=triplequad(@(x,y,z) (y*sin(x)+z*cos(x)),0,pi,0,1,-1,1,1.e-10,@quad)

    7  常微分方程

    1 clear all;
    2 f1=dsolve('Dy-y=sin(x)')
    3 f2=dsolve('Dy-y=sin(x)','x')

    求微分方程的特解

    1 clear all;
    2 dsolve('Dy=a*y','y(0)=b')

    求微分方程的解

    1 clear all;
    2 dsolve('D2y+2*Dy+exp(x)=0','x')
  • 相关阅读:
    POJ 2002 Squares
    POJ 1840 Eqs
    POJ 1759 Garland
    UVA 572 Oil Deposits
    POJ 3278 Catch That Cow
    POJ 2488 A Knight's Journey
    UVA 699 The Falling Leaves
    [Poi1999] 原始生物
    [bzoj3033] 太鼓达人
    [bzoj1123] BLO
  • 原文地址:https://www.cnblogs.com/xiaochi/p/8890790.html
Copyright © 2011-2022 走看看