在继承类中，父类在子类中初始化问题，已解决

#include<iostream>

using namespace std;

//继承与组合混搭情况下，构造和析构调用原则
class Grandfather
{
public:
	Grandfather( char * g)
	{
		this->G_t1=g;
		cout<<"G_t1====== "<<G_t1;
		cout<<"我是顶头的爷爷的构造函数
";
	}

	~Grandfather()
	{
		cout<<"我是顶头的爷爷的析构函数
";
	}
protected:
	char *G_t1;
private:
};
class Father:public Grandfather
{
public:
	Father( char *f):Grandfather("hahahah")
	{
		F_t1=f;
		cout<<"F_t1====== "<<F_t1;
		cout<<"这是父亲的构造函数
";
	}
	~Father()
	{
		cout<<"这是父亲的析构函数 
";
	}
protected:
	char *F_t1;
private:
};
class Child:public Father
{
public:
	Child():Father("dsa"),g1("sfsdfds"),g2("g2")//不懂
	{

		cout<<"这是孩子的构造函数 
";
	}
	~Child()
	{
		cout<<"这是孩子的析构函数 
";
	}
protected:
	int C_t1;
	Grandfather g1;//这里这两句有疑问，为什么Grandfather明明必须有形参，但是为什么这里初始化参数反而不对了呢？
	Grandfather g2;
private:
};

void objplay()
{
	Child c1;
}
int main()
{
	
	objplay();
	system("pause");
	return 0;		
}

　　不明白的是这两句

 但是这好像是套路，必须这么做呢

就像例如：

#include<iostream>

using namespace std;

//继承与组合混搭情况下，构造和析构调用原则
class Grandfather
{
public:
	Grandfather( char * g)
	{
		this->G_t1=g;
		cout<<"G_t1====== "<<G_t1;
		cout<<"我是顶头的爷爷的构造函数
";
	}

	~Grandfather()
	{
		cout<<"我是顶头的爷爷的析构函数
";
	}
protected:
	char *G_t1;
private:
};
class Father:public Grandfather
{
public:
	Father( char *f):Grandfather("hahahah")
	{
		F_t1=f;
		cout<<"F_t1====== "<<F_t1;
		cout<<"这是父亲的构造函数
";
	}
	~Father()
	{
		cout<<"这是父亲的析构函数 
";
	}
protected:
	char *F_t1;
private:
};
class Child:public Father
{
public:
	Child():Father("dsa"),g1("sfsdfds"),g2("g2"),f1("f1")//不懂
	{

		cout<<"这是孩子的构造函数 
";
	}
	~Child()
	{
		cout<<"这是孩子的析构函数 
";
	}
protected:
	int C_t1;
	Father f1;
	Grandfather g1;//这里这两句有疑问，为什么Grandfather明明必须有形参，但是为什么这里初始化参数反而不对了呢？
	Grandfather g2;
private:
};

void objplay()
{
	Child c1;
}
int main()
{
	
	objplay();
	system("pause");
	return 0;		
}

　　运行结果是：

发现一个真理没？只要调用一个Father就必须调用一个爷爷啊

套路