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  • LeetCode Easy: 48. Rotate Image

     一、题目

    You are given an n x n 2D matrix representing an image.

    Rotate the image by 90 degrees (clockwise).

    Note:

    You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.

    Example 1:

    Given input matrix = 
    [
      [1,2,3],
      [4,5,6],
      [7,8,9]
    ],
    
    rotate the input matrix in-place such that it becomes:
    [
      [7,4,1],
      [8,5,2],
      [9,6,3]
    ]
    

    Example 2:

    Given input matrix =
    [
      [ 5, 1, 9,11],
      [ 2, 4, 8,10],
      [13, 3, 6, 7],
      [15,14,12,16]
    ], 
    
    rotate the input matrix in-place such that it becomes:
    [
      [15,13, 2, 5],
      [14, 3, 4, 1],
      [12, 6, 8, 9],
      [16, 7,10,11]
    ]
    

     题意:给定一个矩阵,顺时针旋转90度。
     二、思路

     

     三、代码

    #coding:utf-8
    import numpy as np
    class Solution:
        def rotate(self, matrix):
            """
            :type matrix: List[List[int]]
            :rtype: void Do not return anything, modify matrix in-place instead.
            """
            print("old:",'
    ', matrix)
            n = np.shape(matrix)[0]
            # 沿着副对角线反转
            for i in range(n):
                for j in range(n-i):
                    temp = matrix[i][j]
                    matrix[i][j] = matrix[n-1-j][n-1-i]
                    matrix[n-1-j][n-1-i] = temp
    
            #沿着水平中线反转
            for i in range(n//2):
                for j in range(n):
                    temp = matrix[i][j]
                    matrix[i][j] = matrix[n-1-i][j]
                    matrix[n-1-i][j] = temp
    
            print('new:','
    ', matrix)
    
    if __name__ == '__main__':
        a = [[1,2,3],
             [4,5,6],
             [7,8,9]
            ]
        ss = Solution()
        ss.rotate(a)
    

      

    既然无论如何时间都会过去,为什么不选择做些有意义的事情呢
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  • 原文地址:https://www.cnblogs.com/xiaodongsuibi/p/9006193.html
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