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  • SQL server 2005 时间函数应用 查询出结果为:1天2小时30分钟47秒

    延续上篇随笔,直接放代码了,调用是一样的,现在修改下自定义函数:

    View Code
     1 ------------------------------------------------------          
     2 -- Usage: Convert seconds to Hour:Minute:Second
     3 ------------------------------------------------------          
     4 create  function f_SecondsToHourMinuteSecond(@seconds bigint)          
     5 returns varchar(20)          
     6 as          
     7 begin          
     8   declare @str as varchar(20)  
     9   if @seconds >= 10  --如果秒数大于等于10
    10   begin  
    11     declare @day as varchar(10)
    12     declare @hour as varchar(10)
    13     declare @minute as varchar(10)
    14     declare @second as varchar(10)
    15 
    16     if(@seconds/86400<10) 
    17       begin
    18         set @day='0'+convert(varchar(10),@seconds/86400)
    19       end
    20     else
    21       begin
    22         set @day=convert(varchar(10),@seconds/84600)
    23       end
    24 
    25     if(@seconds%86400/3600 < 10)
    26       begin
    27         set @hour = '0' + convert(varchar(10),@seconds%86400/3600)
    28       end
    29     else
    30       begin
    31         set @hour = convert(varchar(10),@seconds%86400/3600)
    32       end
    33     
    34     if(@seconds%86400%3600/60 < 10)
    35       begin
    36          set @minute = '0' + convert(varchar(10),@seconds%86400%3600/60)
    37       end
    38     else
    39       begin
    40          set @minute = convert(varchar(10),@seconds%86400%3600/60)
    41       end
    42 
    43     if(@seconds%86400%3600%60 < 10)
    44       begin
    45          set @second = '0' + convert(varchar(10),@seconds%86400%3600%60%60)
    46       end
    47     else
    48       begin
    49          set @second = convert(varchar(10),@seconds%86400%3600%60%60)
    50       end
    51     set @str = @day+''+@hour + '小时' + @minute + '分钟' + @second +''
    52   end  
    53   else   --如果秒数小于10
    54   begin  
    55      set @str = '00:00:0'+convert(varchar(20),@seconds)  
    56   end  
    57     return(@str)        
    58 end    


    查询结果如下:

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  • 原文地址:https://www.cnblogs.com/xiaolong617/p/2945989.html
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