poj 3299 Humidex

题目链接:http://poj.org/problem?id=3299

        挺扯蛋的一题，本来想刷点水题，结果让这题的题目给虐了...抽空得好好补补英语了。主要是公式的推导

代码：

#include<iostream>
#include<cstdio>
#include<math.h>
using namespace std;

float e = 2.718281828 ;

float fun1(float h, float d){
    return h-(0.5555*((6.11*pow(e,5417.7530*(1/273.16-1/(d+273.16))))-10.0)) ;
}

float fun2(float t,float d){
    return t+(0.5555*((6.11*pow(e,5417.7530*(1/273.16-1/(d+273.16))))-10.0)) ;
}

float fun3(float t,float h){
    return 1/(1/273.16-log(((h-t)/0.5555+10.0)/6.11)/5417.7530)-273.16 ;
}

int main(){
    char L[100] ;
    char a1, a2 ;
    float t1, t2 ;
    while(true){
        cin >> a1 ;
        if(a1=='E')
            break ;
        cin >> t1 >> a2 >> t2 ;
        if(a1=='D'&&a2=='H')
            printf("T %.1f D %.1f H %.1f\n",fun1(t2,t1),t1,t2) ;
        else if(a1=='H'&&a2=='D')
           printf("T %.1f D %.1f H %.1f\n",fun1(t1,t2),t2,t1) ;
        else if(a1=='T'&&a2=='D')
            printf("T %.1f D %.1f H %.1f\n",t1,t2,fun2(t1,t2)) ;
        else if(a1=='D'&&a2=='T')
            printf("T %.1f D %.1f H %.1f\n",t2,t1,fun2(t2,t1)) ;
        else if(a1=='T'&&a2=='H')
            printf("T %.1f D %.1f H %.1f\n",t1,fun3(t1,t2),t2);
        else if(a1=='H'&&a2=='T')
            printf("T %.1f D %.1f H %.1f\n",t2,fun3(t2,t1),t1) ;

    }
}