Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [-2,1,-3,4,-1,2,1,-5,4]
,
the contiguous subarray [4,-1,2,1]
has the largest sum = 6
.
class Solution { public int maxSubArray(int[] nums) { if(nums==null||nums.length==0) return 0; int maxSum=nums[0];//最大和。初始值要为第一项 int theSum=nums[0];//当前项为止的最大和。初始值要为第一项,不要为0
//如果当前项的最大和小于等于0,那么theSum应该要从该项后面开始重新计算和,因为负数对和没有正帮助。 for(int i=1;i<nums.length;i++){ if(theSum>0) theSum=theSum+nums[i]; else theSum=nums[i];//初始值不为零,则这里初始化时也就不是0, if(maxSum<theSum) maxSum=theSum; } return maxSum; } }
初始为0,若只有一个元素,且为负数,此时就会输出0.不对