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  • [算法]打印N个数组的整体最大Top K

    题目:

    有N个长度不一的数组,所有的数组都是有序的,请从大到小打印这N个数组整体最大的前K个数。

    例如:

    输入含有N行元素的二维数组代表N个一维数组。

    219,405,538,845,971

    148,558

    52,99,348,691

    再输入整数K=5,则打印:

    Top 5:971,845,961,558,538。

    要求:

    1.如果所有数组的元素个数小于K,则从小到大打印所有的数。

    2.时间复杂度为O(KlogN)。

    解答:

    利用堆结构和堆排序完成。

    import java.util.Arrays;
    
    public class Problem_20_PrintMaxTopK {
    
    	public static class HeapNode {
    
    		public int value; 
    
    		public int arrNum; 
    
    		public int index; 
    
    		public HeapNode(int value, int arrNum, int index) {
    
    			this.value = value;
    
    			this.arrNum = arrNum;
    
    			this.index = index;
    
    		}
    
    	}
    
    	public static void printTopK(int[][] matrix, int topK) {
    
    		int heapSize = matrix.length;
    
    		HeapNode[] heap = new HeapNode[heapSize];
    
    		for (int i = 0; i != heapSize; i++) {
    
    			int index = matrix[i].length - 1;
    
    			heap[i] = new HeapNode(matrix[i][index], i, index);
    
    			heapInsert(heap, i);
    
    		}
    
    		System.out.println("TOP " + topK + " : ");
    
    		for (int i = 0; i != topK; i++) {
    
    			if (heapSize == 0) {
    
    				break;
    
    			}
    
    			System.out.print(heap[0].value + " ");
    
    			if (heap[0].index != 0) {
    
    				heap[0].value = matrix[heap[0].arrNum][--heap[0].index];
    
    			} else {
    
    				swap(heap, 0, --heapSize);
    
    			}
    
    			heapify(heap, 0, heapSize);
    
    		}
    
    	}
    
    	public static void heapInsert(HeapNode[] heap, int index) {
    
    		while (index != 0) {
    
    			int parent = (index - 1) / 2;
    
    			if (heap[parent].value < heap[index].value) {
    
    				swap(heap, parent, index);
    
    				index = parent;
    
    			} else {
    
    				break;
    
    			}
    
    		}
    
    	}
    
    	public static void heapify(HeapNode[] heap, int index, int heapSize) {
    
    		int left = index * 2 + 1;
    
    		int right = index * 2 + 2;
    
    		int largest = index;
    
    		while (left < heapSize) {
    
    			if (heap[left].value > heap[index].value) {
    
    				largest = left;
    
    			}
    
    			if (right < heapSize && heap[right].value > heap[largest].value) {
    
    				largest = right;
    
    			}
    
    			if (largest != index) {
    
    				swap(heap, largest, index);
    
    			} else {
    
    				break;
    
    			}
    
    			index = largest;
    
    			left = index * 2 + 1;
    
    			right = index * 2 + 2;
    
    		}
    
    	}
    
    	public static void swap(HeapNode[] heap, int index1, int index2) {
    
    		HeapNode tmp = heap[index1];
    
    		heap[index1] = heap[index2];
    
    		heap[index2] = tmp;
    
    	}
    
    	public static int[][] generateRandomMatrix(int maxRow, int maxCol,
    
    			int maxValue) {
    
    		if (maxRow < 0 || maxCol < 0) {
    
    			return null;
    
    		}
    
    		int[][] matrix = new int[(int) (Math.random() * maxRow) + 1][];
    
    		for (int i = 0; i != matrix.length; i++) {
    
    			matrix[i] = new int[(int) (Math.random() * maxCol) + 1];
    
    			for (int j = 0; j != matrix[i].length; j++) {
    
    				matrix[i][j] = (int) (Math.random() * maxValue);
    
    			}
    
    			Arrays.sort(matrix[i]);
    
    		}
    
    		return matrix;
    
    	}
    
    	public static void printMatrix(int[][] matrix) {
    
    		for (int i = 0; i != matrix.length; i++) {
    
    			for (int j = 0; j != matrix[i].length; j++) {
    
    				System.out.print(matrix[i][j] + " ");
    
    			}
    
    			System.out.println();
    
    		}
    
    	}
    
    	public static void main(String[] args) {
    
    		int[][] matrix = generateRandomMatrix(5, 10, 1000);
    
    		printMatrix(matrix);
    
    		System.out.println("===========================");
    
    		printTopK(matrix, 100);
    
    	}
    
    }
    

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  • 原文地址:https://www.cnblogs.com/xiaomoxian/p/5189333.html
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