zoukankan      html  css  js  c++  java
  • python退出多重循环

    假设一段python程序有多重循环,我们都知道在一个循环当中,用break是退出当前的循环,然后继续下一次循环,但是如何才能跳出多重循环呢,实际就是结束所有的循环。

    思路1::可以定义一个异常类,在需要退出循环的位置,跑出这个异常,就可以了,因为程序在遇到异常的时候,如果没有捕获异常的话,就是直接退出程序的执行,利用这个原理,认为的触发一个异常,然后把这个异常捕获到,就可以实现退出多重循环,而且不结束程序,继续往下执行

    #encoding=utf-8
    class getOutOfLoop(Exception):
        pass

    try:
        for i in range(5):
            for j in range(5):
                for k in range(5):
                    if i == j ==k ==3:
                        raise getOutOfLoop()#抛出一个异常,就会跳出所有循环
                    else:
                        print i,'---',j,'---',k
    except getOutOfLoop:
        pass
    print "done"


    结果:可以看到在循环到特定条件时,直接抛出异常,然后进行捕获,使程序跳出循环后并不结束,而是接着捕获异常的位置后面继续执行。

    D:>python test.py

    0 --- 0 --- 0

    0 --- 0 --- 1

    0 --- 0 --- 2

    0 --- 0 --- 3

    0 --- 0 --- 4

    0 --- 1 --- 0

    0 --- 1 --- 1

    0 --- 1 --- 2

    0 --- 1 --- 3

    0 --- 1 --- 4

    0 --- 2 --- 0

    0 --- 2 --- 1

    0 --- 2 --- 2

    0 --- 2 --- 3

    0 --- 2 --- 4

    0 --- 3 --- 0

    0 --- 3 --- 1

    0 --- 3 --- 2

    0 --- 3 --- 3

    0 --- 3 --- 4

    0 --- 4 --- 0

    0 --- 4 --- 1

    0 --- 4 --- 2

    0 --- 4 --- 3

    0 --- 4 --- 4

    1 --- 0 --- 0

    1 --- 0 --- 1

    1 --- 0 --- 2

    1 --- 0 --- 3

    1 --- 0 --- 4

    1 --- 1 --- 0

    1 --- 1 --- 1

    1 --- 1 --- 2

    1 --- 1 --- 3

    1 --- 1 --- 4

    1 --- 2 --- 0

    1 --- 2 --- 1

    1 --- 2 --- 2

    1 --- 2 --- 3

    1 --- 2 --- 4

    1 --- 3 --- 0

    1 --- 3 --- 1

    1 --- 3 --- 2

    1 --- 3 --- 3

    1 --- 3 --- 4

    1 --- 4 --- 0

    1 --- 4 --- 1

    1 --- 4 --- 2

    1 --- 4 --- 3

    1 --- 4 --- 4

    2 --- 0 --- 0

    2 --- 0 --- 1

    2 --- 0 --- 2

    2 --- 0 --- 3

    2 --- 0 --- 4

    2 --- 1 --- 0

    2 --- 1 --- 1

    2 --- 1 --- 2

    2 --- 1 --- 3

    2 --- 1 --- 4

    2 --- 2 --- 0

    2 --- 2 --- 1

    2 --- 2 --- 2

    2 --- 2 --- 3

    2 --- 2 --- 4

    2 --- 3 --- 0

    2 --- 3 --- 1

    2 --- 3 --- 2

    2 --- 3 --- 3

    2 --- 3 --- 4

    2 --- 4 --- 0

    2 --- 4 --- 1

    2 --- 4 --- 2

    2 --- 4 --- 3

    2 --- 4 --- 4

    3 --- 0 --- 0

    3 --- 0 --- 1

    3 --- 0 --- 2

    3 --- 0 --- 3

    3 --- 0 --- 4

    3 --- 1 --- 0

    3 --- 1 --- 1

    3 --- 1 --- 2

    3 --- 1 --- 3

    3 --- 1 --- 4

    3 --- 2 --- 0

    3 --- 2 --- 1

    3 --- 2 --- 2

    3 --- 2 --- 3

    3 --- 2 --- 4

    3 --- 3 --- 0

    3 --- 3 --- 1

    3 --- 3 --- 2

    done

    思路2:在多重循环中用return,直接进行返回,程序遇到return就会认为程序执行结束,进而退出多个循环,这种情况,执行return后,程序不会继续往下执行,而是直接结束程序

    #encoding=utf-8
    #函数中,用return会退出多重循环
    def test():
        for i in range(5):
            for j in range(5):
                for k in range(5):
                    if i ==j==k==3:
                        return
                    else:
                        print i,'---',j,'---',k
    test()

    结果:

    D:>python test.py
    0 --- 0 --- 0
    0 --- 0 --- 1
    0 --- 0 --- 2
    0 --- 0 --- 3
    0 --- 0 --- 4
    0 --- 1 --- 0
    0 --- 1 --- 1
    0 --- 1 --- 2
    0 --- 1 --- 3
    0 --- 1 --- 4
    0 --- 2 --- 0
    0 --- 2 --- 1
    0 --- 2 --- 2
    0 --- 2 --- 3
    0 --- 2 --- 4
    0 --- 3 --- 0
    0 --- 3 --- 1
    0 --- 3 --- 2
    0 --- 3 --- 3
    0 --- 3 --- 4
    0 --- 4 --- 0
    0 --- 4 --- 1
    0 --- 4 --- 2
    0 --- 4 --- 3
    0 --- 4 --- 4
    1 --- 0 --- 0
    1 --- 0 --- 1
    1 --- 0 --- 2
    1 --- 0 --- 3
    1 --- 0 --- 4
    1 --- 1 --- 0
    1 --- 1 --- 1
    1 --- 1 --- 2
    1 --- 1 --- 3
    1 --- 1 --- 4
    1 --- 2 --- 0
    1 --- 2 --- 1
    1 --- 2 --- 2
    1 --- 2 --- 3
    1 --- 2 --- 4
    1 --- 3 --- 0
    1 --- 3 --- 1
    1 --- 3 --- 2
    1 --- 3 --- 3
    1 --- 3 --- 4
    1 --- 4 --- 0
    1 --- 4 --- 1
    1 --- 4 --- 2
    1 --- 4 --- 3
    1 --- 4 --- 4
    2 --- 0 --- 0
    2 --- 0 --- 1
    2 --- 0 --- 2
    2 --- 0 --- 3
    2 --- 0 --- 4
    2 --- 1 --- 0
    2 --- 1 --- 1
    2 --- 1 --- 2
    2 --- 1 --- 3
    2 --- 1 --- 4
    2 --- 2 --- 0
    2 --- 2 --- 1
    2 --- 2 --- 2
    2 --- 2 --- 3
    2 --- 2 --- 4
    2 --- 3 --- 0
    2 --- 3 --- 1
    2 --- 3 --- 2
    2 --- 3 --- 3
    2 --- 3 --- 4
    2 --- 4 --- 0
    2 --- 4 --- 1
    2 --- 4 --- 2
    2 --- 4 --- 3
    2 --- 4 --- 4
    3 --- 0 --- 0
    3 --- 0 --- 1
    3 --- 0 --- 2
    3 --- 0 --- 3
    3 --- 0 --- 4
    3 --- 1 --- 0
    3 --- 1 --- 1
    3 --- 1 --- 2
    3 --- 1 --- 3
    3 --- 1 --- 4
    3 --- 2 --- 0
    3 --- 2 --- 1
    3 --- 2 --- 2
    3 --- 2 --- 3
    3 --- 2 --- 4
    3 --- 3 --- 0
    3 --- 3 --- 1
    3 --- 3 --- 2

  • 相关阅读:
    从YouTube改版看“移动优先”——8个移动优先网站设计案例赏析
    如何设计出正确的搜索模式?
    20个优秀手机界面扁平化设计,让你一秒看懂扁平化
    更巧妙的表单设计与登陆访问
    子树路径
    选拔赛-最短路
    hiho1050(树的直径)
    逆元
    hiho1303(模线性方程组)
    扩展欧几里德
  • 原文地址:https://www.cnblogs.com/xiaxiaoxu/p/9739415.html
Copyright © 2011-2022 走看看