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  • C调用lua脚本的效率测试

    #include <time.h>

    extern "C"
    {
    #include "lua.h"
    #include "lualib.h"
    #include "lauxlib.h"
    }/* Lua解释器指针 */

    const char LUA_SCRIPT[] =
    "function loop_add(a, b) "
    " local sum = 0 "
    " for i = 1, 10000000 do "
    " sum = sum + a + b "
    " end "
    " return sum "
    "end "
    " "
    "function add(a, b) "
    " return a + b "
    "end "
    ;

    // lua 脚本里面的函数由C调用
    int use_lua_add(lua_State *L, const char *func_name, int x, int y)
    {
    int sum; /* 通过名字得到Lua函数 */
    lua_getglobal(L, func_name); /* 第一个参数 */
    lua_pushnumber(L, x); /* 第二个参数 */
    lua_pushnumber(L, y); /* 调用函数,告知有两个参数,一个返回值 */
    lua_call(L, 2, 1); /* 得到结果 */
    sum = (int)lua_tointeger(L, -1);
    lua_pop(L, 1);
    return sum;
    }

    int main()
    {
    int i, sum = 0;
    clock_t tStart, tStop;

    lua_State *L = lua_open(); /* opens Lua */
    luaL_openlibs(L);
    if (luaL_dostring(L, LUA_SCRIPT)) // Run lua script
    {
    printf("run script failed/n");
    lua_close(L);
    return -1;
    }

    sum = 0;
    tStart = clock();
    for (i = 0; i < 10000000; i++)
    {
    sum += 1 + 1;
    }
    tStop = clock();
    printf("C++: %dms./nThe sum is %u./n",
    (tStop - tStart) * 1000 / CLOCKS_PER_SEC, sum);

    sum = 0;
    tStart = clock();
    sum = use_lua_add(L, "loop_add", 1, 1);
    tStop = clock();
    printf("Lua loop_add: %dms./nThe sum is %u./n",
    (tStop - tStart) * 1000 / CLOCKS_PER_SEC, sum);

    sum = 0;
    tStart = clock();
    for (i = 0; i < 10000000; i++)
    {
    sum += use_lua_add(L, "add", 1, 1);
    }
    tStop = clock();
    printf("Loop lua add: %dms./nThe sum is %u./n",
    (tStop - tStart) * 1000 / CLOCKS_PER_SEC, sum);


    lua_close(L);
    return 0;
    }

    运行结果:

    C++: 31ms.
    The sum is 20000000.
    Lua loop_add: 437ms.
    The sum is 20000000.
    Loop lua add: 2360ms.
    The sum is 20000000.

     

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  • 原文地址:https://www.cnblogs.com/xiayong123/p/3717279.html
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