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  • 376 Wiggle Subsequence 摆动序列

    A sequence of numbers is called a wiggle sequence if the differences between successive numbers strictly alternate between positive and negative. The first difference (if one exists) may be either positive or negative. A sequence with fewer than two elements is trivially a wiggle sequence.
    For example, [1,7,4,9,2,5] is a wiggle sequence because the differences (6,-3,5,-7,3) are alternately positive and negative. In contrast, [1,4,7,2,5] and [1,7,4,5,5] are not wiggle sequences, the first because its first two differences are positive and the second because its last difference is zero.
    Given a sequence of integers, return the length of the longest subsequence that is a wiggle sequence. A subsequence is obtained by deleting some number of elements (eventually, also zero) from the original sequence, leaving the remaining elements in their original order.
    Examples:
    Input: [1,7,4,9,2,5]
    Output: 6
    The entire sequence is a wiggle sequence.

    Input: [1,17,5,10,13,15,10,5,16,8]
    Output: 7
    There are several subsequences that achieve this length. One is [1,17,10,13,10,16,8].

    Input: [1,2,3,4,5,6,7,8,9]
    Output: 2

    Follow up:
    Can you do it in O(n) time?

    详见:https://leetcode.com/problems/wiggle-subsequence/description/

    C++:

    class Solution {
    public:
        int wiggleMaxLength(vector<int>& nums)
        {
            if (nums.empty()) 
            {
                return 0;
            }
            vector<int> p(nums.size(), 1);
            vector<int> q(nums.size(), 1);
            for (int i = 1; i < nums.size(); ++i) 
            {
                for (int j = 0; j < i; ++j) 
                {
                    if (nums[i] > nums[j])
                    {
                        p[i] = max(p[i], q[j] + 1);
                    }
                    else if (nums[i] < nums[j])
                    {
                        q[i] = max(q[i], p[j] + 1);
                    }
                }
            }
            return max(p.back(), q.back());
        }
    };
    

     参考:https://www.cnblogs.com/grandyang/p/5697621.html

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  • 原文地址:https://www.cnblogs.com/xidian2014/p/8848513.html
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