Given an unsorted array of integers, find the length of longest continuous
increasing subsequence.
Example 1:
Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note: Length of the array will not exceed 10,000.
给定一个未排序的整数数组,找到最长连续递增子序列的长度。
class Solution(object):
def findLengthOfLCIS(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
if not nums:
return 0
res = 1
incNum = 1
for i in range(1, len(nums)):
if nums[i] > nums[i - 1]:
incNum += 1
else:
res = max(incNum, res)
incNum = 1
return max(incNum, res)