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  • 674. Longest Continuous Increasing Subsequence 最长连续增长的子序列

    Given an unsorted array of integers, find the length of longest continuous increasing subsequence.

    Example 1:

    Input: [1,3,5,4,7]
    Output: 3
    Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
    Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4. 
    

    Example 2:

    Input: [2,2,2,2,2]
    Output: 1
    Explanation: The longest continuous increasing subsequence is [2], its length is 1. 
    

    Note: Length of the array will not exceed 10,000.

    给定一个未排序的整数数组,找到最长连续递增子序列的长度。
    1. class Solution(object):
    2. def findLengthOfLCIS(self, nums):
    3. """
    4. :type nums: List[int]
    5. :rtype: int
    6. """
    7. if not nums:
    8. return 0
    9. res = 1
    10. incNum = 1
    11. for i in range(1, len(nums)):
    12. if nums[i] > nums[i - 1]:
    13. incNum += 1
    14. else:
    15. res = max(incNum, res)
    16. incNum = 1
    17. return max(incNum, res)






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  • 原文地址:https://www.cnblogs.com/xiejunzhao/p/7501608.html
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