zoukankan      html  css  js  c++  java
  • 553. Optimal Division 最佳分割

    Given a list of positive integers, the adjacent integers will perform the float division. For example, [2,3,4] -> 2 / 3 / 4.

    However, you can add any number of parenthesis at any position to change the priority of operations. You should find out how to add parenthesis to get the maximum result, and return the corresponding expression in string format. Your expression should NOT contain redundant parenthesis.

    Example:

    Input: [1000,100,10,2]
    Output: "1000/(100/10/2)"
    Explanation:
    1000/(100/10/2) = 1000/((100/10)/2) = 200
    However, the bold parenthesis in "1000/((100/10)/2)" are redundant, 
    since they don't influence the operation priority. So you should return "1000/(100/10/2)". Other cases: 1000/(100/10)/2 = 50 1000/(100/(10/2)) = 50 1000/100/10/2 = 0.5 1000/100/(10/2) = 2

    Note:

    1. The length of the input array is [1, 10].
    2. Elements in the given array will be in range [2, 1000].
    3. There is only one optimal division for each test case.
    给定一个正整数的列表,相邻的整数将执行浮点划分。例如,[2,3,4]→2/3/4。 但是,您可以在任何位置添加任意数量的括号来更改操作的优先级。您应该找出如何添加括号以获取最大结果,并返回字符串格式的相应表达式。您的表达式不应包含冗余圆括号。

    1. class Solution(object):
    2. def optimalDivision(self, nums):
    3. """
    4. :type nums: List[int]
    5. :rtype: str
    6. """
    7. A = map(str, nums)
    8. if len(A) <= 2:
    9. return '/'.join(A)
    10. return A[0] + '/(' + '/'.join(A[1:]) + ')'






  • 相关阅读:
    codevs 1199 开车旅行 2012年NOIP全国联赛提高组
    poj 3349 Snowflake Snow Snowflakes
    poj 3264 Balanced Lineup
    求二进制数中1的个数
    20个正则表达式,减少千行代码
    推流脚本
    Navicat 管理工具下载地址,破解版
    emoji表情处理研究
    计算机网络学习
    tcp/ip 学习-通过视频学习
  • 原文地址:https://www.cnblogs.com/xiejunzhao/p/7530653.html
Copyright © 2011-2022 走看看