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  • poj 2100 Graveyard Design

    直接枚举就行了

    #include<iostream>
    #include<stdio.h>
    #include<algorithm>
    #include<iomanip>
    #include<cmath>
    #include<cstring>
    #include<vector>
    #define ll __int64
    #define pi acos(-1.0)
    #define SIZE 1024
    using namespace std;
    const int mod =1000000007;
    vector<ll>p;
    int main(){
        ll i,j,t;
        ll n,sum,num;
        while(cin>>n){
            p.clear();
            i=j=1;
            sum=0;
            num=(ll)sqrt(n*1.0);
            while(j<=num){
                sum+=j*j;
                if(sum>=n){
                    while(sum>n){
                        sum-=i*i;
                        i++;
                    }
                    if(sum==n){
                        p.push_back(i);
                        p.push_back(j);
                    }
                }
                j++;
            }
            cout<<p.size()/2<<endl;
            for(i=0;i<p.size();i+=2){
                cout<<p[i+1]-p[i]+1;
                for(j=p[i];j<=p[i+1];j++){
                    cout<<' '<<j;
                }
                cout<<endl;
            }
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/xin-hua/p/3231820.html
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