zoukankan      html  css  js  c++  java
  • HDOJ 1013

    Digital Roots
    
    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 30962    Accepted Submission(s): 9508
    
    
    Problem Description
    The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit.
    
    For example, consider the positive integer 24. Adding the 2 and the 4 yields a value of 6. Since 6 is a single digit, 6 is the digital root of 24. Now consider the positive integer 39. Adding the 3 and the 9 yields 12. Since 12 is not a single digit, the process must be repeated. Adding the 1 and the 2 yeilds 3, a single digit and also the digital root of 39.
     
    
    Input
    The input file will contain a list of positive integers, one per line. The end of the input will be indicated by an integer value of zero.
     
    
    Output
    For each integer in the input, output its digital root on a separate line of the output.
     
    
    Sample Input
    24
    39
    0
     
    
    Sample Output
    6
    3

    刚开始忽略的数的大小,代码AC

     1 #include <iostream>
     2 using namespace std;
     3 void sum(int n);
     4 int main()
     5 {
     6     int n;
     7     while(cin>>n)
     8     {
     9         if(n == 0)
    10             break;
    11         else
    12         {
    13             sum(n);
    14         }
    15     }
    16     return 0;
    17 }
    18 void sum(int n)
    19 {
    20     int count=0;
    21     while(n>=10)
    22     {
    23         count+=n%10;
    24         n=n/10;
    25     }
    26     count+=n;
    27     if(count>10)
    28         sum(count);
    29     else
    30         cout<<count<<endl;
    31 }

    后来改用按位来做....需要判断是否为0时候,要注意10这种数,最后一位为0也需要判断...因此改用sum是否为0来确定,是否是第一个数字为0

     1 #include <iostream>
     2 using namespace std;
     3 int main()
     4 {
     5     char c=' ';
     6     int n,sum=0;
     7     while(c=getchar())
     8     {
     9         if(sum>=10)
    10                 sum=sum%10+sum/10;
    11         if(c == '\n')
    12         {
    13             if(sum==0)
    14                 break;
    15             cout<<sum<<endl;
    16             sum=0;
    17         }
    18         else
    19         {
    20             n=c-48;
    21             sum+=n;    
    22         }
    23     }
    24     return 0;
    25 }
  • 相关阅读:
    java学习笔记
    androd Sdk manager配置
    50ms延时程序
    89c51中断入口地址表
    打印杨辉三角--队列的应用
    栈的应用--括号匹配
    哈夫曼编码---数据压缩
    PS转手绘
    数据结构学习思路
    第三届蓝桥杯省赛---第39级台阶
  • 原文地址:https://www.cnblogs.com/xing901022/p/2698524.html
Copyright © 2011-2022 走看看