Let S be a sequence of integers s1s_{1}s1, s2s_{2}s2, ........., sns_{n}sn Each integer is is associated with a weight by the following rules:
(1) If is is negative, then its weight is 0.
(2) If is is greater than or equal to 10000, then its weight is 5. Furthermore, the real integer value of sis_{i}si is si−10000s_{i}-10000si−10000 . For example, if sis_{i}si is 101011010110101, then is is reset to 101101101 and its weight is 555.
(3) Otherwise, its weight is 1.
A non-decreasing subsequence of S is a subsequence si1s_{i1}si1, si2s_{i2}si2, ........., siks_{ik}sik, with i1<i2 ... <iki_{1}<i_{2} ... <i_{k}i1<i2 ... <ik, such that, for all 1≤j<k1 leq j<k1≤j<k, we have sij<sij+1s_{ij}<s_{ij+1}sij<sij+1.
A heaviest non-decreasing subsequence of S is a non-decreasing subsequence with the maximum sum of weights.
Write a program that reads a sequence of integers, and outputs the weight of its
heaviest non-decreasing subsequence. For example, given the following sequence:
80 75 73 93 73 73 10101 97 −1 -1 114 −1 10113 118
The heaviest non-decreasing subsequence of the sequence is <73,73,73,101,113,118> with the total weight being 1+1+1+5+5+1=14. Therefore, your program should output 14 in this example.
We guarantee that the length of the sequence does not exceed 2∗1052*10^{5}2∗105
Input Format
A list of integers separated by blanks:s1s_{1}s1, s2s_{2}s2,.........,sns_{n}sn
Output Format
A positive integer that is the weight of the heaviest non-decreasing subsequence.
样例输入
80 75 73 93 73 73 10101 97 -1 -1 114 -1 10113 118
样例输出
14
题目来源
求最长曾序列，dp
1 #include <bits/stdc++.h> 2 #define ll long long 3 using namespace std; 4 const int N = 2e5+10; 5 int a[N*5], dp[N*5]; 6 int main() { 7 int n, num = 0; 8 while(scanf("%d", &n) != EOF) { 9 if(n >= 10000) { 10 for(int i = 0; i < 5; i ++) a[num++] = n - 10000; 11 } else if(n >= 0) a[num++] = n; 12 } 13 for(int i = 0; i <= N*5; i ++) dp[i] = 1000000; 14 for(int i = 0; i < num; i ++) { 15 *upper_bound(dp, dp+num, a[i]) = a[i]; 16 } 17 cout << lower_bound(dp,dp+num,1000000)-dp << endl ; 18 return 0; 19 }