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  • Leetcode: Merge/Insert Interval

    题目

    Given a collection of intervals, merge all overlapping intervals.

    For example,
    Given [1,3],[2,6],[8,10],[15,18],
    return [1,6],[8,10],[15,18].

    Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

    You may assume that the intervals were initially sorted according to their start times.

    Example 1:
    Given intervals [1,3],[6,9], insert and merge [2,5] in as [1,5],[6,9].

    Example 2:
    Given [1,2],[3,5],[6,7],[8,10],[12,16], insert and merge [4,9] in as [1,2],[3,10],[12,16].

    This is because the new interval [4,9] overlaps with [3,5],[6,7],[8,10].

     
    思路:
    1. 模拟题
    2. Insert Interval 是 Merge Interval 的扩展, 将 newInterval 插入到 Intervals 即可转化成 Merge Interval
     
    代码
    bool sortInterval(const Interval &i1, const Interval &i2) {
    	return i1.start < i2.start;
    }
    class Solution {
    public:
        vector<Interval> merge(vector<Interval> &intervals) {
    		vector<Interval> newVec;
    		if(intervals.size() <= 0)
    			return newVec;
    		
    		sort(intervals.begin(), intervals.end(), sortInterval);
    		for(int i = 0; i < intervals.size(); i ++) {
    			Interval nextInt = intervals[i];
    			if(i == intervals.size()-1) {
    				newVec.push_back(nextInt);
    				break;
    			}
    			Interval tmp = intervals[i+1];
    			while(tmp.start <= nextInt.end) {
    				nextInt.end = max(tmp.end, nextInt.end);
    				i++;
    				if(i+1<intervals.size())
    					tmp = intervals[i+1];
    				else {
    					newVec.push_back(nextInt);
    					return newVec;
    				}
    			}
    			newVec.push_back(nextInt);
    		}
    		return newVec;
        }
    };
    

      

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  • 原文地址:https://www.cnblogs.com/xinsheng/p/3513245.html
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