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  • 4500 小Q系列故事——屌丝的逆袭

     1 #include <iostream>
     2 #include <algorithm>
     3 #include <vector>
     4 #include <cstdio>
     5 
     6 #define MAX 20 + 3
     7 
     8 using namespace std;
     9 
    10 const int dx[] = {-1,1,0,0};
    11 const int dy[] = {0,0,-1,1};
    12 
    13 int main(){
    14     int n,m;
    15     while( cin>>n>>m && n && m ){
    16         int pos[MAX][MAX] = {0};
    17         for(int i = 1; i <= n; i ++ )
    18             for(int j = 1; j <= m ; j ++ )
    19                 cin>>pos[i][j];
    20 
    21         int value[MAX][MAX] = {0};
    22         for(int i = 1; i <=n ; i ++ ){
    23             for(int j = 1; j <=m; j ++){
    24                 for(int k = 0; k < 4; k ++ ){
    25                     if(pos[ i+dx[k] ][ j+dy[k] ]*pos[i][j] < 0) value[i][j] += abs(pos[ i+dx[k] ][ j+dy[k] ]);
    26                     else value[i][j] -= abs(pos[ i+dx[k] ][ j+dy[k] ]);
    27                 }
    28             }
    29         }
    30 
    31         int maxV = -1<<30, idx,idy;
    32         for(int i = 1; i <= n; i ++ ){
    33             for(int j = 1; j <= m ; j ++ ){
    34                 if(maxV < value[i][j]){
    35                     maxV = value[i][j];
    36                     idx = i;
    37                     idy = j;
    38                 }
    39             }
    40         }
    41         cout<<idx << " "<<idy<<" "<<maxV<<endl;
    42     }
    43 
    44     return 0;
    45 }
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  • 原文地址:https://www.cnblogs.com/xiongqiangcs/p/3006046.html
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