zoukankan      html  css  js  c++  java
  • ural 1011. Conductors

    1011. Conductors

    Time Limit: 2.0 second
    Memory Limit: 64 MB

    Background

    Everyone making translations from English to Russian knows an English phrase "Naked conductor runs along the bus". It has two very different meanings.

    Problem

    Every bus in the Ekaterinburg city has a special man (or woman) called conductor. When you ride the bus, you have to give money to the conductor. We know that there are more than P% conductors and less than Q% conductors of all citizens of Ekaterinburg. Your task is to determine a minimal possible number of Ekaterinburg citizens. By percentage, we know that there are more than P% conductors and less than Q% conductors of all Russian citizens in this city

    Input

    Two numbers P,Q such that 0.01 ≤ P, Q ≤ 99.99. Numbers are given with 2 digits precision. These numbers are separated by some spaces or "end of line" symbols.

    Output

    The minimal number of Ekaterinburg citizens.

    Sample

    inputoutput
    13
    14.1
    
    15

    Hint

    If there are 15 citizens and 2 conductors among them in Ekaterinburg, then there are 13 1/3 % conductors of all citizens.
     
    #include <iostream>
    #include <cstdio>
    #include <cmath>
    #include <algorithm>
    #define EPS 10e-8
    
    using namespace std;int main(){
        double p,q;
        cin >>p>>q;
        double  k = 1;
        p+=EPS;q-=EPS;
        while(1){
            int a = int(k*p)/100,b=int(k*q)/100;
            //cout<<ceil(a)<<" "<<floor(b)<<endl;
            if(a!=b) break;
            k++;
        }
        cout<< k<<endl;
        return 0;
    }
    
  • 相关阅读:
    看到关于java资料比较全的,自己收藏
    ie6下pnghack——css方案
    git基本操作
    购物车功能实现
    jquery学习:获取位置position(),offset(),scrollTop困惑
    Datax3.0使用说明
    Scala字符串操作
    Scala中class、object、case class、case object区别
    Scala构造函数
    scala数组操作
  • 原文地址:https://www.cnblogs.com/xiongqiangcs/p/3035763.html
Copyright © 2011-2022 走看看