1013. K-based Numbers. Version 3
Time Limit: 2.0 second
Memory Limit: 64 MB
Memory Limit: 64 MB
Let’s consider K-based numbers, containing exactly N digits. We define a number to be valid if itsK-based notation doesn’t contain two successive zeros. For example:
- 1010230 is a valid 7-digit number;
- 1000198 is not a valid number;
- 0001235 is not a 7-digit number, it is a 4-digit number.
Given two numbers N and K, you are to calculate an amount of valid K based numbers, containing Ndigits.
You may assume that 2 ≤ K ≤ 10; N ≥ 2; N + K ≤ 1800.
Input
The numbers N and K in decimal notation separated by the line break.
Output
The result in decimal notation.
Sample
input | output |
---|---|
2 10 |
90 |
import java.io.*; import java.util.*; import java.math.*; public class aa{ public static void main(String args[]){ Scanner cin = new Scanner(new BufferedInputStream(System.in)); int n = cin.nextInt(),k = cin.nextInt(); BigInteger dp[] = new BigInteger[2000]; dp[1] = BigInteger.valueOf(k-1); dp[2] = BigInteger.valueOf(k*(k-1)); for(int i = 3; i <= n ; i ++ ){ dp[i] = BigInteger.valueOf(0).add(dp[i-1]).add(dp[i-2]); dp[i] = dp[i].multiply(BigInteger.valueOf(k-1)); } System.out.println(dp[n]); } }