直接上代码,有三种方法,第三种调用库函数效率最高
# ! /usr/bin/env python # encoding:utf-8 if __name__ == '__main__': a = [1,2,3,4,5] b = [2,3,6,7] u =[] dif =[] intersec = [] '''方法一,最简单的方法,容易想到的''' for item in a: u.append(item) if item in b: intersec.append(item) if item not in b: dif.append(item) for key in b: u.append(key) print('u is ',list(set(u))) #u is [1, 2, 3, 4, 5, 6, 7] print('dif is ', dif) #dif is [1, 4, 5] print('intersec is ', intersec) #intersec is [2, 3] '''方法二''' a = [1,2,3,4,5] b = [2,3,6,7] intersec = [item for item in a if item in b] dif = [item for item in a if item not in b] #不能放在最后,因为b.extend时b已经被改变了 b.extend([i for i in a]) u = b print('u is ', list(set(u))) # u is [1, 2, 3, 4, 5, 6, 7] print('dif is ', dif) # dif is [1, 4, 5] print('intersec is ', intersec) # intersec is [2, 3] '''方法三,调用库函数,集合操作''' a = [1,2,3,4,5] b = [2,3,6,7] intersec = list(set(a).intersection(set(b))) u = list(set(a).union(set(b))) dif = list(set(a).difference(set(b))) print('u is ', u) # u is [1, 2, 3, 4, 5, 6, 7] print('dif is ', dif) # dif is [1, 4, 5] print('intersec is ', intersec) # intersec is [2, 3]