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  • 单链表逆置

    重写单链表逆置,熟能生巧~

    #include <iostream>
    #include <cstdlib>
    
    using namespace std;
    
    typedef struct List{
    
        int num;
        struct List *next;
    
    }ListNode,*pListNode;
    
    void display(ListNode *pHead)
    {
    
        while(pHead)
        {
            cout<<pHead->num<<"--";
            pHead = pHead->next;
        }
    
        cout<<endl;
    }
    
    ListNode* ReverseListNode(ListNode *pHead)
    {
        ListNode* curNode = pHead;
        ListNode* preNode = pHead->next;
        ListNode* nextNode = preNode->next;
        curNode->next = NULL;
        while(nextNode)
        {
            preNode->next = curNode;
            curNode = preNode;
            preNode = nextNode;
            nextNode = nextNode->next;
        }
    
        preNode->next = curNode;
    
        return preNode;
    }
    
    
    int main()
    {
        int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
    
        ListNode* pHead = (struct List*)malloc(sizeof(struct List));
        pHead->num = 0;
        pHead->next = NULL;
    
        for(int i = 0; i < 10; i++)
        {
             ListNode *pNode = (struct List*)malloc(sizeof(struct List));
             pNode->num = arr[i];
             pNode->next = NULL;
    
             pNode->next = pHead->next;
             pHead->next = pNode;
    
        }
    
        ListNode* pTemp = pHead;
    
        while(pTemp)
        {
            cout<<pTemp->num<<"--";
            pTemp = pTemp->next;
        }
    
        cout<<endl;
        ListNode* pTemp2 = ReverseListNode(pHead);
        while(pTemp2)
        {
            cout<<pTemp2->num<<"--";
            pTemp2 = pTemp2->next;
        }
    
        cout<<endl;
    
        return 0;
    
    }
    
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  • 原文地址:https://www.cnblogs.com/xshang/p/7173010.html
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