zoukankan      html  css  js  c++  java
  • [LC] 1055. Shortest Way to Form String

    From any string, we can form a subsequence of that string by deleting some number of characters (possibly no deletions).

    Given two strings source and target, return the minimum number of subsequences of source such that their concatenation equals target. If the task is impossible, return -1.

    Example 1:

    Input: source = "abc", target = "abcbc"
    Output: 2
    Explanation: The target "abcbc" can be formed by "abc" and "bc", which are subsequences of source "abc".
    

    Example 2:

    Input: source = "abc", target = "acdbc"
    Output: -1
    Explanation: The target string cannot be constructed from the subsequences of source string due to the character "d" in target string.


    class Solution {
        public int shortestWay(String source, String target) {
            int res = 0;
            int i = 0;
            while (i < target.length()) {
                int next = scan(source, target, i);
                if (i == next) {
                    return -1;
                }
                i = next;
                res += 1;
            }
            return res;
        }
        
        private int scan(String source, String target, int i) {
            for (char c: source.toCharArray()) {
                if (i != target.length()) {
                    char cur = target.charAt(i);
                    if (c == cur) {
                        i += 1;
                    }
                }
            }
            return i;
        }   
    }
  • 相关阅读:
    ffmpeg
    HDU 1031 Design T-Shirt
    HDU 1029 Ignatius and the Princess IV
    HDU 1022 Train Problem I
    HDU 1017 A Mathematical Curiosity
    HDU 1015 Safecracker
    HDU 1002 A + B Problem II
    HDU 1070 Milk
    高精度算法(一)
    codeblocks 使用心得
  • 原文地址:https://www.cnblogs.com/xuanlu/p/12294528.html
Copyright © 2011-2022 走看看