zoukankan      html  css  js  c++  java
  • [LC] 123. Best Time to Buy and Sell Stock III

    Say you have an array for which the ith element is the price of a given stock on day i.

    Design an algorithm to find the maximum profit. You may complete at most two transactions.

    Note: You may not engage in multiple transactions at the same time (i.e., you must sell the stock before you buy again).

    Example 1:

    Input: [3,3,5,0,0,3,1,4]
    Output: 6
    Explanation: Buy on day 4 (price = 0) and sell on day 6 (price = 3), profit = 3-0 = 3.
                 Then buy on day 7 (price = 1) and sell on day 8 (price = 4), profit = 4-1 = 3.

    Example 2:

    Input: [1,2,3,4,5]
    Output: 4
    Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.
                 Note that you cannot buy on day 1, buy on day 2 and sell them later, as you are
                 engaging multiple transactions at the same time. You must sell before buying again.
    

    Example 3:

    Input: [7,6,4,3,1]
    Output: 0
    Explanation: In this case, no transaction is done, i.e. max profit = 0.

    class Solution {
        public int maxProfit(int[] prices) {
            int buy1 = Integer.MIN_VALUE, buy2 = Integer.MIN_VALUE;
            int sell1 = 0, sell2 = 0;
            for (int price: prices) {
                sell2 = Math.max(sell2, buy2 + price);
                buy2 = Math.max(buy2, sell1 - price);
                sell1 = Math.max(sell1, price + buy1);
                buy1 = Math.max(buy1, -price);
            }
            return sell2;
        }
    }
  • 相关阅读:
    Docker PHP 扩展配置
    PHP 打水印功能
    MYSQL的主从复制
    CentOS7开启防火墙及特定端口
    非常全面的讲解Hosts文件
    STL的erase()陷阱-迭代器失效总结
    scons使用
    SecureCRT 使用技巧
    atomic, spinlock and mutex性能比较
    内存池的实现(二)
  • 原文地址:https://www.cnblogs.com/xuanlu/p/12450983.html
Copyright © 2011-2022 走看看