bzoj1176

题解：

和上一题差不多

就加上一个初始值

代码：

#include<bits/stdc++.h>
const int N=1000005;
using namespace std;
int n,m,cnt,s,sum[N],ans1[N],pos[N],ans[N];
struct date{int op,x,y,v,id;}qs[N];
int comp(date x,date y){return x.x<y.x;}
void add(int x,int y){for (int i=x;i<=n;i+=i&-i)sum[i]+=y;}
int  query(int x)
{
    int temp=0;
    for (int i=x;i;i-=i&-i)temp+=sum[i];
    return temp;
}
void solve(int l,int r)
{
    if (l==r) return;
    int mid=(l+r)/2,temp=0;
    solve(l,mid);solve(mid+1,r);
    sort(qs+l,qs+mid+1,comp);
    sort(qs+mid+1,qs+r+1,comp);
    int i=l,j=mid+1;
    while (j<=r)
     {
        while (qs[i].op==2&&i<=mid) i++;
        while (qs[j].op==1&&j<=r) j++;
        if (i<=mid&&qs[i].x<=qs[j].x) add(qs[i].y,qs[i].v),i++,temp=i-1;
        else if (j<=r) ans[qs[j].id]+=query(qs[j].y),j++;
     }
    for (int t=l;t<=temp;t++) if (qs[t].op==1) add(qs[t].y,-qs[t].v); 
}
int main()
{
    memset(ans,0,sizeof(ans));
    memset(sum,0,sizeof(sum));
    int op,x1,x2,y1,y2;
    scanf("%d%d",&s,&n),m=cnt=0;
    for (;;)
     {
        scanf("%d",&op);
        if (op==1)
         {
            qs[++m].op=op,qs[m].id=m;
            scanf("%d%d%d",&qs[m].x,&qs[m].y,&qs[m].v);
         }
        else
         {
            if (op==2)
             {
                scanf("%d%d%d%d",&x1,&y1,&x2,&y2);
                pos[++cnt]=m;
                qs[++m].op=op,qs[m].x=x1-1,qs[m].y=y1-1,qs[m].id=m;
                ans1[m]+=s*(x2-x2+1)*(y2-y1+1);
                qs[++m].op=op,qs[m].x=x2,qs[m].y=y2,qs[m].id=m;        
                qs[++m].op=op,qs[m].x=x1-1,qs[m].y=y2,qs[m].id=m;
                qs[++m].op=op,qs[m].x=x2,qs[m].y=y1-1,qs[m].id=m;
             }
            else break;
         }
     }
    solve(1,m);
    for (int i=1;i<=cnt;i++)
     printf("%d
",ans[pos[i]+1]+ans[pos[i]+2]-ans[pos[i]+3]-ans[pos[i]+4]);
}