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  • 【php】php输出jquery的轮询,5秒跳转指定url

    1、在php中直接输出jquery的轮询,5秒后跳转指定url

    2、代码稍微改动,即可在html中使用

    3、代码:

    public function alpha(){
                $html = '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
                        <html xmlns="http://www.w3.org/1999/xhtml">
                        <head>
                        <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
                        <script src="http://weixin.jimuc.com/app/resource/js/lib/jquery-1.11.1.min.js"></script>
                        <title>积慕商城午夜订购</title>
                        </head>
                        <body>';
                $html.= "<img src='http://pms.jimuc.com/index.php?m=file&f=read&t=png&fileID=130' style=' 100%;height: 100%;'/>
                        <input class='loginTime' value='5' type='hidden'>";
                $html.=    "<script type='text/javascript'>
                            var loginTime = parseInt($('.loginTime').val());
                            var time = setInterval(function(){
                                console.log(loginTime);
                                loginTime = loginTime-1;
                                $('.loginTime').val(loginTime);
                                if(loginTime == 0){
                                    window.location.href = '$url';
                                }
                                  
                            },1000);
                         </script>";
                $html.= '</body>
                         </html>';
                print_r($html);exit;
    }

    4、效果:

     

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  • 原文地址:https://www.cnblogs.com/xuzhengzong/p/9765442.html
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