面试题41-2：和为s的连续正数序列

题目描述

输入一个正数s，打印出所有和为s的连续正数序列（至少含有两个数）。例如输入15，由于1+2+3+4+5=4+5+6=7+8=15，所以结果打印出3个连续序列1~5、4~6和7~8。

题目分析

剑指Offer（纪念版）P216

代码实现

void FindContinuousSequence(int sum)
{
    if(sum < 3)
        return;

    int small = 1; 
    int big = 2;
    int middle = (1 + sum) / 2;
    int curSum = small + big;

    while(small < middle)
    {
        if(curSum == sum)
            PrintContinuousSequence(small, big);

        while(curSum > sum && small < middle)
        {
            curSum -= small;
            small ++;

            if(curSum == sum)
                PrintContinuousSequence(small, big);
        }

        big ++;
        curSum += big;
    }
}

void PrintContinuousSequence(int small, int big)
{
    for(int i = small; i <= big; ++ i)
        printf("%d ", i);

    printf("
");
}