dfs序编号后跑权值主席树
但写起来是真的麻烦,总是wa,只能拿出模板过了
#include<bits/stdc++.h>
const int N = 100001;
using namespace std;
struct node {
int to, ne;
} e[N<<1];
int n, m, len, l1, l2;
int id[N], rk[N], eid[N], re[N];
int he[N], a[N], b[N];
int val[N << 5], lc[N << 5], rc[N << 5], rt[N << 5];
void add(int x, int y) {
e[++l2].to = y, e[l2].ne = he[x];
he[x] = l2;
}
void dfs(int x, int fa) {
id[x] = ++l1, rk[l1] = x;
for(int i = he[x]; i; i = e[i].ne) {
int y = e[i].to;
if(y == fa) continue;
dfs(y, x);
}
eid[x] = l1;
}
int change(int rt, int l, int r, int x, int y) {
int now = ++len;
lc[now] = lc[rt], rc[now] = rc[rt], val[now] = val[rt] + 1;
if(l == r) {
re[l] = y;
return now;
}
int mid = (l + r) >> 1;
if(x <= mid)
lc[now] = change(lc[rt], l, mid, x, y);
else
rc[now] = change(rc[rt], mid + 1, r, x, y);
return now;
}
int query(int u, int v, int l, int r, int k) {
if(l == r)
return re[l];
int mid = (l + r) >> 1, s = val[lc[v]] - val[lc[u]], res;
if(s >= k)
res = query(lc[u], lc[v], l, mid, k);
else
res = query(rc[u], rc[v], mid + 1, r, k - s);
return res;
}
int main() {
scanf("%d", &n);
for(int i = 1; i <= n; i++)
scanf("%d", &a[i]), b[i] = a[i];
sort(b + 1, b + n + 1);
for( int i = 1; i < n; i++) {
int x, y;
scanf("%d%d", &x, &y);
add(x, y);
add(y, x);
}
dfs(1, 0);
for(int i = 1; i <= n; i++) {
a[rk[i]] = lower_bound(b + 1, b + n + 1, a[rk[i]]) - b;
rt[i] = change(rt[i - 1], 1, n, a[rk[i]], rk[i]);
}
scanf("%d", &m);
for(int i = 1; i <= m; i++) {
int x, k;
scanf("%d%d", &x, &k);
printf("%d
", query(rt[id[x] - 1], rt[eid[x]], 1, n, k));
}
return 0;
}