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  • 344. 反转字符串

    编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

    不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

    你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

    示例 1:

    输入:["h","e","l","l","o"]
    输出:["o","l","l","e","h"]
    示例 2:

    输入:["H","a","n","n","a","h"]
    输出:["h","a","n","n","a","H"]

    来源:力扣(LeetCode)
    链接:https://leetcode-cn.com/problems/reverse-string

    class Solution:
        def reverseString(self, s: List[str]) -> None:
            """
            Do not return anything, modify s in-place instead.
            """
            s.reverse()
    class Solution:
        def reverseString(self, s: List[str]) -> None:
            """
            Do not return anything, modify s in-place instead.
            """
            for i in range(len(s)//2):
                s[i],s[len(s)-i-1]=s[len(s)-i-1],s[i]
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  • 原文地址:https://www.cnblogs.com/xxxsans/p/13781744.html
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