P39-习题2-4

/*输入两个正整数m,n,求（i^2+1/i),从m到n的和*/
#include<stdio.h>
int main(void)
{
    int m,n,i;
    double product,result;
/*result为单个元素的解，product为所有解的和*/
    printf("Enter m:");
    scanf("%d",&m);
    printf("Enter n:");
    scanf("%d",&n);

    product=0;
/*从m到n依次循环求解*/
    for(i=m;i<=n;i++){
        result=(i*i)+(1/i);
        printf("%d",result);
/*将单个元素所求解累加起来*/
        product=product+result;

    }
    printf("product=%.2f
",product);

    return 0;
}