题中有一个坑点,就是模式串可以相同,并且全部计数。
#include <bits/stdc++.h>
using namespace std;
const int maxn=1e6+10;
const int N=maxn;
char str[maxn];
struct Dfa {
int trie[N][26],cnt;
int e[N];
int fail[N];
char ch;
void init(char c) {
memset(trie,0,sizeof(trie));
memset(e,0,sizeof(e));
memset(fail,0,sizeof(fail));
cnt=0;
ch=c;
}
void insert(char * s) {
int p=0;
for (int i=0;s[i];i++) {
int to=s[i]-ch;
if (trie[p][to]==0) {
trie[p][to]=++cnt;
}
p=trie[p][to];
}
e[p]++;
}
void build() {
queue<int> q;
for (int i=0;i<26;i++) {
if (trie[0][i]) {
q.push(trie[0][i]);
}
}
while (!q.empty()) {
int root=q.front();
q.pop();
for (int i=0;i<26;i++) {
if (trie[root][i]) {
fail[trie[root][i]]=trie[fail[root]][i];
q.push(trie[root][i]);
}
else {
trie[root][i]=trie[fail[root]][i];
}
}
}
}
long long query(char * s) {
long long ans=0;
int p=0;
for (int i=0;s[i];i++) {
p=trie[p][s[i]-ch];//第一层的空节点k trie[0][k]=0
for (int j=p;j&&~e[j];j=fail[j]) {
ans+=e[j];
e[j]=-1;
}
}
return ans;
}
}dfa;
int main()
{
int n;
dfa.init('a');
scanf("%d",&n);
while (n--) {
scanf("%s",str);
dfa.insert(str);
}
dfa.build();
scanf("%s",str);
printf("%lld
",dfa.query(str));
return 0;
}