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  • HDU 4879 ZCC loves march (2014多校2-1008,数据结构,STL,模拟题)

    题目:

    http://acm.hdu.edu.cn/showproblem.php?pid=4879

    题意:

    给一个n*m的矩阵,有n个人,t次操作,操作有以下两种:

    1、令编号x的人上下左右移动

    2、令与编号x的人同行同列的人聚集到x这里,输出花费

    方法:

    使用两个set,一个维护x轴,一个维护y轴

    一个map<point,int>,表示这一个point有多少个人

    然后根据要求的操作直接操作即可,nlgn复杂度

    注意:

    1、由于set或者map是红黑树,所以删除节点的后,内部节点重排,it++会变化,需要重新查询给迭代器it赋值,这里一直RE

    2、计算两者距离时,计算xi-xj和yi-yj时需要mod,否则乘起来会爆long long

    代码:

      1 // #pragma comment(linker, "/STACK:102400000,102400000")
      2 #include <cstdio>
      3 #include <iostream>
      4 #include <cstring>
      5 #include <string>
      6 #include <cmath>
      7 #include <set>
      8 #include <list>
      9 #include <map>
     10 #include <iterator>
     11 #include <cstdlib>
     12 #include <vector>
     13 #include <queue>
     14 #include <stack>
     15 #include <algorithm>
     16 #include <functional>
     17 using namespace std;
     18 typedef long long LL;
     19 #define ROUND(x) round(x)
     20 #define FLOOR(x) floor(x)
     21 #define CEIL(x) ceil(x)
     22 const int maxn = 100010;
     23 const int maxm = 0;
     24 const LL mod = 1e9 + 7;
     25 const int inf = 0x3f3f3f3f;
     26 const LL inf64 = 0x3f3f3f3f3f3f3f3fLL;
     27 const double INF = 1e30;
     28 const double eps = 1e-6;
     29 const int P[4] = {0, 0, -1, 1};
     30 const int Q[4] = {1, -1, 0, 0};
     31 const int PP[8] = { -1, -1, -1, 0, 0, 1, 1, 1};
     32 const int QQ[8] = { -1, 0, 1, -1, 1, -1, 0, 1};
     33 LL n, m;
     34 LL ans = 0;
     35 int id;
     36 LL d;
     37 struct Point
     38 {
     39     LL x, y;
     40     int id;
     41     Point(LL _x = -1, LL _y = -1, int _id = -1): x(_x), y(_y), id(_id) {}
     42     bool operator == (const Point &o) const
     43     {
     44         return x == o.x && y == o.y;
     45     }
     46 } node[maxn];
     47 struct cmp1
     48 {
     49     bool operator () (const Point &A, const Point &B) const
     50     {
     51         if (A.x == B.x) return A.y < B.y;
     52         return A.x < B.x;
     53     }
     54 };
     55 struct cmp2
     56 {
     57     bool operator () (const Point &A, const Point &B) const
     58     {
     59         if (A.y == B.y) return A.x < B.x;
     60         return A.y < B.y;
     61     }
     62 };
     63 set<Point, cmp1> s1;
     64 set<Point, cmp2> s2;
     65 map<Point, int, cmp1> mp;
     66 void debug()
     67 {
     68     cout << "debug:" << endl;
     69     cout << "s1:" << endl;
     70     for (set<Point>::iterator it = s1.begin(); it != s1.end(); it++)
     71     {
     72         cout << it->x << " " << it->y << endl;
     73     }
     74     cout << "s2:" << endl;
     75     for (set<Point>::iterator it = s2.begin(); it != s2.end(); it++)
     76     {
     77         cout << it->x << " " << it->y << endl;
     78     }
     79     cout << "mp:" << endl;
     80     for (map<Point, int>::iterator it = mp.begin(); it != mp.end(); it++)
     81     {
     82         cout << it->first.x << " " << it->first.y << " " << it->second << endl;
     83     }
     84     cout << endl;
     85 }
     86 void init()
     87 {
     88     mp.clear();
     89     s1.clear();
     90     s2.clear();
     91     ans = 0;
     92 }
     93 void add(Point p)
     94 {
     95     if (mp.count(p) == 0)
     96     {
     97         mp[p] = 1;
     98         s1.insert(p);
     99         s2.insert(p);
    100     }
    101     else mp[p]++;
    102 }
    103 void del(Point p)
    104 {
    105     map<Point, int, cmp1>::iterator ite = mp.find(p);
    106     ite->second--;
    107     if (ite->second == 0)
    108     {
    109         mp.erase(ite);
    110         s1.erase(p);
    111         s2.erase(p);
    112     }
    113 }
    114 void input()
    115 {
    116     s1.insert(Point(-1, 0));
    117     s1.insert(Point(m + 1, 0));
    118     s2.insert(Point(0, -1));
    119     s2.insert(Point(0, m + 1));
    120     // s2.insert(Point(0, m + 2));
    121     for (LL i = 1; i <= n; i++)
    122     {
    123         scanf("%I64d%I64d", &node[i].x, &node[i].y);
    124         node[i].id = i;
    125         add(node[i]);
    126     }
    127 }
    128 LL dis(Point a, Point b)
    129 {
    130     return ((((a.x - b.x) % mod) * ((a.x - b.x) % mod) % mod) + (((a.y - b.y) % mod) * ((a.y - b.y) % mod) % mod)) % mod;
    131 }
    132 void exq()
    133 {
    134     ans = 0;
    135     Point tt = node[id];
    136     map<Point, int, cmp1>::iterator ite = mp.find(tt);
    137 
    138     set<Point, cmp1>::iterator it1 = s1.find(tt);
    139     set<Point, cmp1>::iterator L1 = it1, R1 = it1;
    140     for (; L1->x == it1->x; --L1); ++L1;
    141     for (; R1->x == it1->x; ++R1);
    142     for (set<Point, cmp1>::iterator it = L1; it != R1;)
    143     {
    144         // cout << "it1: " << it->x << " " << it->y << endl;
    145         if (it == it1)
    146         {
    147             it++;
    148             continue;
    149         }
    150         Point nt = *it;
    151 
    152         node[it->id] = tt;
    153         int cnt = mp[nt];
    154         ans += cnt * dis(tt, nt) % mod;
    155         ans %= mod;
    156         ite->second += cnt;
    157         it++;
    158         Point ntt = *it;
    159         mp.erase(nt);
    160         s1.erase(nt);
    161         s2.erase(nt);
    162         it = s1.find(ntt);
    163     }
    164 
    165     set<Point, cmp2>::iterator it2 = s2.find(tt);
    166     set<Point, cmp2>::iterator L2 = it2, R2 = it2;
    167     for (; L2->y == it2->y; --L2); ++L2;
    168     for (; R2->y == it2->y; ++R2);
    169     // cout << "R2: " << R2->x << " " << R2->y << endl;
    170     for (set<Point, cmp2>::iterator it = L2; it != R2;)
    171     {
    172         // cout << "it2: " << it->x << " " << it->y << endl;
    173         // if (it == R2) break;
    174         if (it == it2)
    175         {
    176             it++;
    177             continue;
    178         }
    179         Point nt = *it;
    180         node[it->id] = tt;
    181         int cnt = mp[nt];
    182         ans += cnt * dis(tt, nt) % mod;
    183         ans %= mod;
    184         ite->second += cnt;
    185         //set<Point, cmp2>::iterator tmp = it;
    186         it++;
    187         Point ntt = *it;
    188         mp.erase(nt);
    189         s1.erase(nt);
    190         s2.erase(nt);
    191         it = s2.find(ntt);
    192     }
    193 
    194     printf("%I64d
    ", ans);
    195 }
    196 void exu()
    197 {
    198     Point pre = node[id];
    199     Point now = Point(pre.x - d, pre.y, pre.id);
    200     node[id] = now;
    201     del(pre);
    202     add(now);
    203 }
    204 void exd()
    205 {
    206     Point pre = node[id];
    207     Point now = Point(pre.x + d, pre.y, pre.id);
    208     node[id] = now;
    209     del(pre);
    210     add(now);
    211 }
    212 void exl()
    213 {
    214     Point pre = node[id];
    215     Point now = Point(pre.x , pre.y - d, pre.id);
    216     node[id] = now;
    217     del(pre);
    218     add(now);
    219 }
    220 void exr()
    221 {
    222     Point pre = node[id];
    223     Point now = Point(pre.x , pre.y + d, pre.id);
    224     node[id] = now;
    225     del(pre);
    226     add(now);
    227 }
    228 void solve()
    229 {
    230     int T;
    231     scanf("%d", &T);
    232     char str[10];
    233     while (T--)
    234     {
    235         // debug();
    236         scanf("%s", str);
    237         // puts(str);
    238         if (str[0] == 'Q')
    239         {
    240             scanf("%d", &id);
    241             id ^= (int)ans;
    242             // cout << "id: " << ans << " " << id << endl;
    243             exq();
    244         }
    245         else
    246         {
    247             scanf("%d%I64d", &id, &d);
    248             id ^= (int)ans;
    249             // cout << "id: " << ans << " " << id << endl;
    250             if (str[0] == 'U')
    251                 exu();
    252             else if (str[0] == 'D')
    253                 exd();
    254             else if (str[0] == 'L')
    255                 exl();
    256             else
    257                 exr();
    258         }
    259         // debug();
    260     }
    261 }
    262 void output()
    263 {
    264     //
    265 }
    266 int main()
    267 {
    268     // std::ios_base::sync_with_stdio(false);
    269 // #ifndef ONLINE_JUDGE
    270 //     freopen("in.cpp", "r", stdin);
    271 // #endif
    272 
    273     while (~scanf("%I64d%I64d", &n, &m))
    274     {
    275         init();
    276         input();
    277         solve();
    278         output();
    279     }
    280     return 0;
    281 }
    View Code
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  • 原文地址:https://www.cnblogs.com/xysmlx/p/3870861.html
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