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  • 19.2.8 [LeetCode 55] Jump Game

    Given an array of non-negative integers, you are initially positioned at the first index of the array.

    Each element in the array represents your maximum jump length at that position.

    Determine if you are able to reach the last index.

    Example 1:

    Input: [2,3,1,1,4]
    Output: true
    Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index.
    

    Example 2:

    Input: [3,2,1,0,4]
    Output: false
    Explanation: You will always arrive at index 3 no matter what. Its maximum
                 jump length is 0, which makes it impossible to reach the last index.
     1 class Solution {
     2 public:
     3     bool canJump(vector<int>& nums) {
     4         if (nums.size() == 1)return true;
     5         int reach = nums[0], prereach = 0, n = nums.size();
     6         while (1) {
     7             int nextreach = reach;
     8             bool flag = false;
     9             for (int i = prereach + 1; i <= reach && i < n; i++) {
    10                 if (i + nums[i] > nextreach) {
    11                     nextreach = i + nums[i];
    12                     flag = true;
    13                 }
    14             }
    15             if (nextreach >= n - 1)
    16                 return true;
    17             if (!flag)return false;
    18             prereach = reach;
    19             reach = nextreach;
    20         }
    21         return false;
    22     }
    23 };
    View Code

    指路→JUMP GAME II

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  • 原文地址:https://www.cnblogs.com/yalphait/p/10356443.html
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