zoukankan      html  css  js  c++  java
  • 19.2.8 [LeetCode 55] Jump Game

    Given an array of non-negative integers, you are initially positioned at the first index of the array.

    Each element in the array represents your maximum jump length at that position.

    Determine if you are able to reach the last index.

    Example 1:

    Input: [2,3,1,1,4]
    Output: true
    Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index.
    

    Example 2:

    Input: [3,2,1,0,4]
    Output: false
    Explanation: You will always arrive at index 3 no matter what. Its maximum
                 jump length is 0, which makes it impossible to reach the last index.
     1 class Solution {
     2 public:
     3     bool canJump(vector<int>& nums) {
     4         if (nums.size() == 1)return true;
     5         int reach = nums[0], prereach = 0, n = nums.size();
     6         while (1) {
     7             int nextreach = reach;
     8             bool flag = false;
     9             for (int i = prereach + 1; i <= reach && i < n; i++) {
    10                 if (i + nums[i] > nextreach) {
    11                     nextreach = i + nums[i];
    12                     flag = true;
    13                 }
    14             }
    15             if (nextreach >= n - 1)
    16                 return true;
    17             if (!flag)return false;
    18             prereach = reach;
    19             reach = nextreach;
    20         }
    21         return false;
    22     }
    23 };
    View Code

    指路→JUMP GAME II

  • 相关阅读:
    2015年中国500强企业
    汇编语言
    oracle数据库学习路线
    OI生涯回忆录
    NOIP 2020游记
    CF223B Two Strings 题解
    CSP-S 2020游记
    CSP/NOIP 注意事项(2020)
    Luogu P6583 回首过去 题解
    Luogu P2210 Haywire 题解
  • 原文地址:https://www.cnblogs.com/yalphait/p/10356443.html
Copyright © 2011-2022 走看看