只要统计每一个左右分别有多少比他高的去min,然后求和
#include<algorithm>
#include<iostream>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<cmath>
using namespace std;
typedef long long LL;
#define lowbit(x) (x & (-x))
#define N 300010
struct Node
{
int h,id;
}a[N];
int n;
int cnt;
LL ans;
int c[N];
int read()
{
int x=0;
char ch=getchar();
while (ch<'0' || ch>'9')
ch=getchar();
while (ch>='0' && ch<='9')
{
x=x*10+ch-'0';
ch=getchar();
}
return x;
}
bool cmp(Node x,Node y)
{
return x.h>y.h;
}
void add(int x)
{
while (x<=n)
c[x]++,x+=lowbit(x);
}
int query(int x)
{
int res(0);
while (x)
res+=c[x],x-=lowbit(x);
return res;
}
int main()
{
n=read();
for (int i=1;i<=n;i++)
a[i].h=read(),a[i].id=i;
sort(a+1,a+n+1,cmp);
int k=1;
for (int i=1;i<=n;i++)
{
if (a[i].h!=a[i-1].h)
while (k<i)
add(a[k++].id);
cnt=query(a[i].id);
ans+=min(cnt,k-1-cnt);
}
printf("%lld",ans);
return 0;
}