zoukankan      html  css  js  c++  java
  • UVA 146 ID Codes(下一个排列)


    C - ID Codes
    Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu
    Appoint description: 

    Description

    Download as PDF


     ID Codes 

    It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and thereby to counter a chronic breakdown in law and order, the Government decides on a radical measure--all citizens are to have a tiny microcomputer surgically implanted in their left wrists. This computer will contains all sorts of personal information as well as a transmitter which will allow people's movements to be logged and monitored by a central computer. (A desirable side effect of this process is that it will shorten the dole queue for plastic surgeons.)

    An essential component of each computer will be a unique identification code, consisting of up to 50 characters drawn from the 26 lower case letters. The set of characters for any given code is chosen somewhat haphazardly. The complicated way in which the code is imprinted into the chip makes it much easier for the manufacturer to produce codes which are rearrangements of other codes than to produce new codes with a different selection of letters. Thus, once a set of letters has been chosen all possible codes derivable from it are used before changing the set.

    For example, suppose it is decided that a code will contain exactly 3 occurrences of `a', 2 of `b' and 1 of `c', then three of the allowable 60 codes under these conditions are:

          abaabc
          abaacb
          ababac

    These three codes are listed from top to bottom in alphabetic order. Among all codes generated with this set of characters, these codes appear consecutively in this order.

    Write a program to assist in the issuing of these identification codes. Your program will accept a sequence of no more than 50 lower case letters (which may contain repeated characters) and print the successor code if one exists or the message `No Successor' if the given code is the last in the sequence for that set of characters.

    Input and Output

    Input will consist of a series of lines each containing a string representing a code. The entire file will be terminated by a line consisting of a single #.

    Output will consist of one line for each code read containing the successor code or the words `No Successor'.

    Sample input

    abaacb
    cbbaa
    #

    Sample output

    ababac
    No Successor

    #include<iostream>
    #include<algorithm>
    #include<stdio.h>
    #include<queue>
    #include<vector>
    #include<string.h>
    #include<map>
    using namespace std;
    int main()
    {
        //freopen("in.txt","r",stdin);
        char s[60];
        while(gets(s)!=NULL){
            if(!strcmp(s,"#"))return 0;
            int len=strlen(s);
            int solve=0;
            for(int i=len-2;!solve&&i>=0;i--)
            for(int j=len-1;j>i;j--)
            {
                if(s[j]>s[i]){
                    solve=1;
                    char t=s[i];
                    s[i]=s[j];
                    s[j]=t;
                    sort(s+i+1,s+len);
                    break;
                }
            }
            if(solve)puts(s);
            else puts("No Successor");
        }
        return 0;
    }

    STL

    #include<iostream>
    #include <algorithm>
    #include <cstdio>
    #include <cstring>
    using namespace std;
    char s[50];
    int main()
    {
    	while(gets(s) != NULL && s[0] != '#')
    	{
    		if(next_permutation(s, s + strlen(s)))
    			printf("%s
    ", s);
    		else
    			printf("No Successor
    ");
    	}
    	return 0;
    }
    







  • 相关阅读:
    个人管理:提高你的搜商
    敏捷个人:提供更多文档下载,并转载一篇敏捷个人读书笔记
    个人管理: 激励你的一句话
    敏捷个人 从Scrum实践来思考如何导入价值观
    信息系统开发平台OpenExpressApp 如何解决ComboBox.TextProperty绑定带来问题的来龙去脉
    敏捷个人 敏捷个人价值观,欢迎提出你的意见和你的价值观
    使用VS2010的CodedUI来做自己的自动化测试框架
    .Net4下的MEF(Managed Extensibility Framework) 架构简介
    IronRuby - 快速在半小时学习Ruby基础知识
    敏捷个人 项目网站文档页签增加blog链接
  • 原文地址:https://www.cnblogs.com/yangykaifa/p/6744991.html
Copyright © 2011-2022 走看看