zoukankan      html  css  js  c++  java
  • HDU 1564 Play a game(巴什博弈)

    Play a game

    Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 1297    Accepted Submission(s): 1056


    Problem Description
    New Year is Coming! 
    ailyanlu is very happy today! and he is playing a chessboard game with 8600. 
    The size of the chessboard is n*n. A stone is placed in a corner square. They play alternatively with 8600 having the first move. Each time, player is allowed to move the stone to an unvisited neighbor square horizontally or vertically. The one who can't make a move will lose the game. If both play perfectly, who will win the game?

     

    Input
    The input is a sequence of positive integers each in a separate line. 
    The integers are between 1 and 10000, inclusive,(means 1 <= n <= 10000) indicating the size of the chessboard. The end of the input is indicated by a zero.
     

    Output
    Output the winner ("8600" or "ailyanlu") for each input line except the last zero. 
    No other characters should be inserted in the output.
     

    Sample Input
    2 0
     

    Sample Output
    8600
     

    题意:给定一个n*n的表格,在一个角上放入一块石头,然后两个人轮流移动石头,仅仅能水平和竖直移动石子。并且不能移到已经訪问的格子。最后没法移动的玩家为输者。如今输入随意的n输出谁输谁胜。

    这个随便画两个就能非常easy的推算出胜负。

    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <algorithm>
    #include <climits>
    
    using namespace std;
    
    int a,b;
    
    int main(){
        //freopen("in.txt","r",stdin);
        //(author : CSDN iaccepted)
    	int n;
    	while(scanf("%d",&n) && n){
    		if(n&1){
    			printf("ailyanlu
    ");
    		}else{
    			printf("8600
    ");
    		}
    	}
        return 0;
    }
    



  • 相关阅读:
    Linux下启动时间优化专题
    如何展开Linux Memory Management学习?
    《Systems Performance》阅读笔记及收获
    Linux时间子系统之四:Timer在用户和内核空间流程
    Win7 下安装ubuntu14.04双系统
    ubuntu 上使用valgrind
    Observer模式
    从C++到java
    gcc 0长数组学习
    Linux中10个有用的命令行补齐命令
  • 原文地址:https://www.cnblogs.com/yangykaifa/p/6752811.html
Copyright © 2011-2022 走看看