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  • 复制对象属性:只复制需要的属性值,目标对象中原来的值不变(反射)

    使用反射(性能很差,自测是cglib-beanmap性能的50分之1左右):

    /**
         * 复制对象属性:只复制需要的属性值,目标对象中原来的值不变
         * 只适用于2个相同对象
         * @param from 要复制的对象
         * @param to 目标对象
         * @throws Exception
         */
        @SuppressWarnings("unchecked")
        public static void copyPropertiesExclude(Object from, Object to) throws Exception {
            if(!from.getClass().equals(to.getClass())){
                throw new RuntimeException("对象不是同一类型,fromClass:"+from.getClass()+",toClass:"+to.getClass());
            }
            Method[] fromMethods = from.getClass().getDeclaredMethods();
            Method[] toMethods = to.getClass().getDeclaredMethods();
            Method fromMethod = null, toMethod = null;
            String fromMethodName = null, toMethodName = null;
            for (int i = 0; i < fromMethods.length; i++) {
                fromMethod = fromMethods[i];
                fromMethodName = fromMethod.getName();
                if (!fromMethodName.contains("get")) {
                    continue;
                }
                toMethodName = "set" + fromMethodName.substring(3);
                toMethod = findMethodByName(toMethods, toMethodName);
                //如果方法为null,不处理
                if (toMethod == null) {
                    continue;
                }
                Object value = fromMethod.invoke(from, new Object[0]);
                //如果值为空,不处理
                if(value == null) {
                    continue;
                }
                //集合类判空处理
                if(value instanceof Collection) {
                    Collection newValue = (Collection)value;
                    if(newValue.size() <= 0)
                        continue;
                }
                toMethod.invoke(to, new Object[] {value});
            }
        }
    
        /**
         * 从方法数组中获取指定名称的方法
         *
         * @param methods
         * @param name
         * @return
         */
        public static Method findMethodByName(Method[] methods, String name) {
            for (int j = 0; j < methods.length; j++) {
                if (methods[j].getName().equals(name))
                    return methods[j];
            }
            return null;
        }
    逃避不一定躲得过,面对不一定最难过
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  • 原文地址:https://www.cnblogs.com/yangzhenlong/p/5778631.html
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