Insertion Sort List 题解
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题目来源:https://leetcode.com/problems/insertion-sort-list/description/
Description
Sort a linked list using insertion sort.
Solution
class Solution {
private:
void insert(ListNode* &head, int x) {
if (head == NULL) {
head = new ListNode(x);
} else {
if (x <= head -> val) {
ListNode* node = new ListNode(x);
node -> next = head;
head = node;
return;
}
ListNode* preNode = head;
ListNode* curNode = head -> next;
while (curNode != NULL) {
if (preNode -> val <= x && x <= curNode -> val) {
ListNode* node = new ListNode(x);
preNode -> next = node;
node -> next = curNode;
return;
}
preNode = curNode;
curNode = curNode -> next;
}
preNode -> next = new ListNode(x);
}
}
public:
ListNode* insertionSortList(ListNode* head) {
ListNode* curNode = head;
ListNode* resHead = NULL;
while (curNode != NULL) {
insert(resHead, curNode -> val);
curNode = curNode -> next;
}
return resHead;
}
};
解题描述
这道题考察的是插入排序,我考虑的做法是遍历原来的链表,每次将取到的数值在新的链表中找到相应的位置,然后拆开新链表,将新的节点插入进去再接上前后的节点。