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  • oracle 中如何定位重要(消耗资源多)的SQL

    oracle 中如何定位重要(消耗资源多)的SQL

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    标题:oracle 中如何定位重要(消耗资源多)的SQL

    作者:惜分飞©版权所有[未经本人同意,不得以任何形式转载,否则有进一步追究法律责任的权利.]

    1、查看值得怀疑的SQL

    select substr(to_char(s.pct,'99.00'),2)||'%'load,
           s.executions executes,
           p.sql_text
    from(select address,
                   disk_reads,
                   executions,
                   pct,
                   rank()over(order by disk_reads desc) ranking
             from(select address,
                           disk_reads,
                           executions,
                          100*ratio_to_report(disk_reads)over() pct
                     from sys.v_$sql
                    where command_type!=47)
            where disk_reads>50*executions) s,
           sys.v_$sqltext p
    where s.ranking<=5
      and p.address=s.address
    order by 1, s.address, p.piece;

    2、查看消耗内存多的sql

    select b.username,
           a. buffer_gets,
           a.executions,
           a.disk_reads / decode(a.executions, 0, 1, a.executions),
           a.sql_text SQL
      from v$sqlarea a, dba_users b
     where a.parsing_user_id = b.user_id
       and a.disk_reads > 10000
     order by disk_reads desc;

    3、查看逻辑读多的SQL

    select*
    from(select buffer_gets, sql_text
             from v$sqlarea
            where buffer_gets>500000
            order by buffer_gets desc)
    where rownum<=30;

    4、查看执行次数多的SQL

    select sql_text, executions
      from (select sql_text, executions from v$sqlarea order by executions desc)
     where rownum < 81;

    5、查看读硬盘多的SQL

    select sql_text, disk_reads
    from(select sql_text, disk_reads from v$sqlarea order by disk_reads desc)
    where rownum<21;

    6、查看排序多的SQL

    select sql_text, sorts
    from(select sql_text, sorts from v$sqlarea order by sorts desc)
    where rownum<21;

    7、分析的次数太多,执行的次数太少,要用绑变量的方法来写sql

    select substr(sql_text, 1, 80) "sql", count(*), sum(executions) "totexecs"
      from v$sqlarea
     where executions < 5
     group by substr(sql_text, 1, 80)
    having count(*) > 30
     order by 2;
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  • 原文地址:https://www.cnblogs.com/yaoyangding/p/14784576.html
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