leetcode7 Reverse Integer

"""
Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123
Output: 321
Example 2:
Input: -123
Output: -321
Example 3:
Input: 120
Output: 21
"""
"""
为了防止溢出，本题需要先转str。再转int
还要考虑正负
考虑超出范围 返回0
用到了切片str[::-1],逆序
"""
class Solution:
    def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        x = int(str(x)[::-1]) if x >= 0 else - int(str(-x)[::-1])
        return x if x < 2147483648 and x >= -2147483648 else 0