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  • OpenCV approxPolyDP 多边拟合函数

    pproxPolyDP 主要功能是把一个连续光滑曲线折线化,对图像轮廓点进行多边形拟合。

    原理图:对比之前黑点连线,之后蓝色连线:

    C++: void approxPolyDP(InputArray curve, OutputArray approxCurve, double epsilon, bool closed)

    参数详解;

    InputArray curve:一般是由图像的轮廓点组成的点集

    OutputArray approxCurve:表示输出的多边形点集

    double epsilon:主要表示输出的精度,就是另个轮廓点之间最大距离数,5,6,7,,8,,,,,

    bool closed:表示输出的多边形是否封闭

     1 #include <opencv2/opencv.hpp>    
     2 #include <stdio.h>    
     3 #include <stdlib.h>    
     4 #include <iostream>  
     5  
     6  
     7 using namespace cv;  
     8 using namespace std;  
     9  
    10  
    11 int main(int argc, char** argv)  
    12 {  
    13     Mat img = imread("4.jpg", -1);
    14     pyrDown(img, img, Size(img.cols/2, img.rows/2), 4);
    15     imshow("img", img);imwrite("img.jpg", img);
    16  
    17     //通过canny算法找轮廓,这样 findcontours 的结果会好些
    18     Mat canny_out;
    19     Canny(img, canny_out, 45, 127, 3, false);
    20     imshow("canny_out", canny_out);imwrite("canny_out.jpg", canny_out);
    21  
    22     //寻找轮廓
    23     vector<vector<Point>> contours;
    24     vector<Vec4i> hierachy;
    25     findContours(canny_out, contours, hierachy, RETR_TREE, CV_CHAIN_APPROX_SIMPLE, Point(-1,-1));
    26     drawContours(img, contours, -1, Scalar(0,0,255), 1, 8, hierachy);
    27     
    28     //定义圆形、方形、旋转矩形、椭圆的存储容器
    29     vector<vector<Point>> contours_ploy(contours.size());
    30     vector<Rect> rects_ploy(contours.size());
    31     vector<Point2f> circle_centers(contours.size());
    32     vector<float> circle_radius(contours.size());
    33     vector<RotatedRect> RotatedRect_ploy;//注意:由于下面赋值的过程中有个点数大于5的条件,所以这里没有直接初始化,才有下面pushback的方法添加值。
    34     vector<RotatedRect> ellipse_ploy;//注意,这里是画椭圆,但是容器类型是 RotatedRect
    35  
    36     //将结果放到各自的容器中
    37     for (size_t i = 0; i< contours.size(); i++)
    38     {
    39         approxPolyDP(contours[i], contours_ploy[i], 5, true);
    40         rects_ploy[i] = boundingRect(contours_ploy[i]);
    41         minEnclosingCircle(contours_ploy[i], circle_centers[i], circle_radius[i]);
    42  
    43         if (contours_ploy[i].size() >5)
    44         {
    45             RotatedRect temp1 = minAreaRect(contours_ploy[i]);
    46             RotatedRect_ploy.push_back(temp1);
    47  
    48             RotatedRect temp2 = fitEllipse(contours_ploy[i]);
    49             ellipse_ploy.push_back(temp2);
    50         }
    51     }
    52  
    53     //定义最终绘图的图片
    54     Mat draw_rect(img.size(), img.type(), Scalar::all(0)), 
    55         draw_rotateRect(img.size(), img.type(), Scalar::all(0)), 
    56         draw_circle(img.size(), img.type(), Scalar::all(0)), 
    57         draw_ellipse(img.size(), img.type(), Scalar::all(0));
    58  
    59     //绘图圆形、矩形
    60     RNG rng(12345);
    61     for (size_t i = 0; i<contours.size(); i++)
    62     {
    63         Scalar color = Scalar(rng.uniform(0,255), rng.uniform(0,255), rng.uniform(0,255));
    64         rectangle(draw_rect, rects_ploy[i], color, 1, 8);
    65         circle(draw_circle, circle_centers[i], circle_radius[i], color, 1, 8);
    66     }
    67     imshow("draw_rect", draw_rect);imwrite("draw_rect.jpg", draw_rect);
    68     imshow("draw_circle", draw_circle);imwrite("draw_circle.jpg", draw_circle);
    69  
    70     //绘图椭圆形、旋转矩形
    71     Point2f pot[4];
    72     for (size_t i = 0; i<ellipse_ploy.size(); i++)
    73     {
    74         Scalar color = Scalar(rng.uniform(0,255), rng.uniform(0,255), rng.uniform(0,255));
    75         ellipse(draw_ellipse, ellipse_ploy[i], color, 1, 8);
    76  
    77         RotatedRect_ploy[i].points(pot);
    78         for(int j=0; j<4; j++)
    79         {
    80             line(draw_rotateRect, pot[j], pot[(j+1)%4], color);
    81         }
    82     }
    83     imshow("draw_ellipse", draw_ellipse);imwrite("draw_ellipse.jpg", draw_ellipse);
    84     imshow("draw_rotateRect", draw_rotateRect);imwrite("draw_rotateRect.jpg", draw_rotateRect);
    85  
    86  
    87     waitKey();
    88     return 1;
    89 }  

     

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  • 原文地址:https://www.cnblogs.com/ybqjymy/p/14333577.html
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