zoukankan      html  css  js  c++  java
  • hoj 1138 LC Display

    /*
    
    题目:
        模拟输出数字时钟
    
    分析:
        先把答案都只为空格,然后枚举每一个数字,在相应的答案数组上做修改,这样的话,只需
        做出来了数字8,其他的都可以实现了。代码很简练,只有100来行
    
    */
    #include <cstdio>
    #include <cstring>
    #include <iostream>
    
    using namespace std;
    
    const int X = 205;
    
    char map[X][X],s[X];
    int n;
    
    int main()
    {
        freopen("sum.in","r",stdin);
        freopen("sum.out","w",stdout);
        while(scanf("%d%s",&n,s),n||s[0]!='0')
        {
            int id;
            int y = 0;
            int len = strlen(s);
            for(int i=0;i<2*n+3;i++)
            {
                for(int j=0;j<len*(n+3)-1;j++)
                    map[i][j] = ' ';
                map[i][len*(n+3)-1] = '\0';
            }
            for(int q=0;s[q];q++)
            {
                id = s[q]-'0';
                if(id==0)
                {
                    for(int i=y+1;i<y+n+1;i++)
                        map[0][i] = map[2*n+2][i] = '-';
                    for(int i=1;i<=n;i++)
                        map[i][y] = map[i+n+1][y] = map[i][y+n+1] = map[i+n+1][y+n+1] = '|';
                }
                else if(id==1)
                {
                    for(int i=1;i<=n;i++)
                        map[i][y+n+1] = map[i+n+1][y+n+1] = '|';
                }
                else if(id==2)
                {
                    for(int i=y+1;i<y+n+1;i++)
                        map[0][i] = map[n+1][i] = map[2*n+2][i] = '-';
                    for(int i=1;i<=n;i++)
                        map[i+n+1][y] = map[i][y+n+1] = '|';
                }
                else if(id==3)
                {
                    for(int i=y+1;i<y+n+1;i++)
                        map[0][i] = map[n+1][i] = map[2*n+2][i] = '-';
                    for(int i=1;i<=n;i++)
                        map[i][y+n+1] = map[i+n+1][y+n+1] = '|';
                }
                else if(id==4)
                {
                    for(int i=y+1;i<y+n+1;i++)
                        map[n+1][i]= '-';
                    for(int i=1;i<=n;i++)
                        map[i][y] = map[i][y+n+1] = map[i+n+1][y+n+1] = '|';
                }
                else if(id==5)
                {
                    for(int i=y+1;i<y+n+1;i++)
                        map[0][i] = map[n+1][i] = map[2*n+2][i] = '-';
                    for(int i=1;i<=n;i++)
                        map[i][y] = map[i+n+1][y+n+1] = '|';
                }
                else if(id==6)
                {
                    for(int i=y+1;i<y+n+1;i++)
                        map[0][i] = map[n+1][i] = map[2*n+2][i] = '-';
                    for(int i=1;i<=n;i++)
                        map[i][y] = map[i+n+1][y] = map[i+n+1][y+n+1] = '|';
                }
                else if(id==7)
                {
                    for(int i=y+1;i<y+n+1;i++)
                        map[0][i] = '-';
                    for(int i=1;i<=n;i++)
                        map[i][y+n+1] = map[i+n+1][y+n+1] = '|';
                }
                else if(id==8)
                {
                    for(int i=y+1;i<y+n+1;i++)
                        map[0][i] = map[n+1][i] = map[2*n+2][i] = '-';
                    for(int i=1;i<=n;i++)
                        map[i][y] = map[i+n+1][y] = map[i][y+n+1] = map[i+n+1][y+n+1] = '|';
                }
                else
                {
                    for(int i=y+1;i<y+n+1;i++)
                        map[0][i] = map[n+1][i] = map[2*n+2][i] = '-';
                    for(int i=1;i<=n;i++)
                        map[i][y] = map[i][y+n+1] = map[i+n+1][y+n+1] = '|';
                }
                y += n+3;
            }
            for(int i=0;i<(2*n+3);i++)
                puts(map[i]);
            puts("");
        }
    
        return 0;
    }
  • 相关阅读:
    UVA12125 March of the Penguins (最大流+拆点)
    UVA 1317 Concert Hall Scheduling(最小费用最大流)
    UVA10249 The Grand Dinner(最大流)
    UVA1349 Optimal Bus Route Design(KM最佳完美匹配)
    UVA1212 Duopoly(最大流最小割)
    UVA1395 Slim Span(kruskal)
    UVA1045 The Great Wall Game(二分图最佳匹配)
    UVA12168 Cat vs. Dog( 二分图最大独立集)
    hdu3488Tour(KM最佳完美匹配)
    UVA1345 Jamie's Contact Groups(最大流+二分)
  • 原文地址:https://www.cnblogs.com/yejinru/p/2608070.html
Copyright © 2011-2022 走看看