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  • hdu 4738 桥

    题目:还是自己看题目吧

    trick:当不连通时不需要人去炸。否则,当桥的费用为0时当然需要一个人去炸。。。

    #include <set>
    #include <map>
    #include <list>
    #include <cmath>
    #include <queue>
    #include <stack>
    #include <string>
    #include <vector>
    #include <cstdio>
    #include <cstring>
    #include <iostream>
    #include <algorithm>
    
    using namespace std;
    
    typedef long long ll;
    typedef unsigned long long ull;
    
    #define debug puts("here")
    #define rep(i,n) for(int i=0;i<n;i++)
    #define rep1(i,n) for(int i=1;i<=n;i++)
    #define REP(i,a,b) for(int i=a;i<=b;i++)
    #define foreach(i,vec) for(unsigned i=0;i<vec.size();i++)
    #define pb push_back
    #define RD(n) scanf("%d",&n)
    #define RD2(x,y) scanf("%d%d",&x,&y)
    #define RD3(x,y,z) scanf("%d%d%d",&x,&y,&z)
    #define RD4(x,y,z,w) scanf("%d%d%d%d",&x,&y,&z,&w)
    #define All(vec) vec.begin(),vec.end()
    #define MP make_pair
    #define PII pair<int,int>
    #define PQ priority_queue
    #define cmax(x,y) x = max(x,y)
    #define cmin(x,y) x = min(x,y)
    #define Clear(x) memset(x,0,sizeof(x))
    /*
    
    #pragma comment(linker, "/STACK:1024000000,1024000000")
    
    int size = 256 << 20; // 256MB
    char *p = (char*)malloc(size) + size;
    __asm__("movl %0, %%esp
    " :: "r"(p) );
    
    */
    
    char IN;
    bool NEG;
    inline void Int(int &x){
        NEG = 0;
        while(!isdigit(IN=getchar()))
            if(IN=='-')NEG = 1;
        x = IN-'0';
        while(isdigit(IN=getchar()))
            x = x*10+IN-'0';
        if(NEG)x = -x;
    }
    inline void LL(ll &x){
        NEG = 0;
        while(!isdigit(IN=getchar()))
            if(IN=='-')NEG = 1;
        x = IN-'0';
        while(isdigit(IN=getchar()))
            x = x*10+IN-'0';
        if(NEG)x = -x;
    }
    
    /******** program ********************/
    
    const int MAXN = 1005;
    const int INF = 1e9;
    
    int low[MAXN],dfn[MAXN],dep;
    int po[MAXN],tol;
    int best;
    
    struct Edge{
        int y,cost,id,next;
    }edge[MAXN*MAXN<<1];
    
    void add(int x,int y,int cost,int id){
        edge[++tol].y = y;
        edge[tol].cost = cost;
        edge[tol].id = id;
        edge[tol].next = po[x];
        po[x] = tol;
    }
    
    void dfs(int x,int fid){
        dfn[x] = low[x] = ++ dep;
        for(int i=po[x];i;i=edge[i].next){
            int y = edge[i].y;
            int id = edge[i].id;
            if(id==fid)continue;
            if(!dfn[y]){
                dfs(y,id);
                cmin(low[x],low[y]);
                if(low[y]>dfn[x]){
                    if(edge[i].cost<best)
                        best = edge[i].cost;
                }
            }else cmin(low[x],dfn[y]);
        }
    }
    
    int main(){
    
    #ifndef ONLINE_JUDGE
        freopen("sum.in","r",stdin);
        //freopen("sum.out","w",stdout);
    #endif
    
        int size = 256 << 20; // 256MB
        char *p = (char*)malloc(size) + size;
        __asm__("movl %0, %%esp
    " :: "r"(p) );
    
        int n,m,x,y,cost;
        while(RD2(n,m),n||m){
            Clear(po);
            tol = 0;
            rep1(i,m){
                RD3(x,y,cost);
                if(x>n||y>n)continue;
                add(x,y,cost,i);
                add(y,x,cost,i);
            }
    
            dep = 0;
            Clear(dfn);
            best = INF;
            int ok = 0;
    
            rep1(i,n)
                if(!dfn[i]){
                    ok ++;
                    dfs(i,0);
                }
            if(best==0)best = 1;
            if(ok>1)best = 0;
            printf("%d
    ",best==INF?-1:best);
        }
    
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/yejinru/p/3323114.html
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