多项式,因为每次的x相同,所以把a和b相加就行了,然后找对称轴,找离对称轴最近的整数点,然而我却写了个暴力,没看x
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
using namespace std;
const int N = 100005;
inline int read()
{
int x = 0 , f = 1; char ch = getchar();
while(ch < '0' || ch > '9') {if(ch == '-') f = -1; ch = getchar();}
while(ch >= '0' && ch <= '9') {x = (x << 3) + (x << 1) + (ch ^ 48); ch = getchar();}
return x * f;
}
int T , n , m;
long long a , b , c;
int main()
{
freopen("shopping.in","r",stdin);
freopen("shopping.out","w",stdout);
T = read();
while(T --> 0)
{
a = 0; b = 0; c = 0;
n = read(); m = read();
for(int i = 1;i <= n;i ++) {a += read(); b += read(); c += read();}
double tmp = (double)b / ((double)a * (double)(-2));
tmp = max(tmp,(double)1); tmp = min(tmp,(double)m);
double res = floor(tmp);
printf("%d
",(tmp - res) < 0.50000000 ? (int)res : (int)res + 1);
}
fclose(stdin);
fclose(stdout);
return 0;
}