向sqlite数据库插入和读取图片数据 (for ios)
假定数据库中存在表 test_table(name,image), 下面代码将图片文件test.png的二进制数据写到sqlite数据库:
char *name = "test";
NSString * nameString = [NSString stringWithCString:name encoding:NSUTF8StringEncoding];
NSString * filePath = [[NSBundle mainBundle] pathForResource:nameString ofType:@"png"];
if ([[NSFileManager defaultManager] fileExistsAtPath:filePath])
{
NSData * imgData = UIImagePNGRepresentation([UIImage imageWithContentsOfFile:filePath]);
const char * sequel = "insert into test_table(name,image) values(?,?)";
sqlite3_stmt * update;
if (sqlite3_prepare_v2(database, sequel, -1, &update, NULL) == SQLITE_OK)
{
sqlite3_bind_text(update, 1, name, -1, NULL);
sqlite3_bind_blob(update, 2, [imgData bytes], [imgData length], NULL);
if( sqlite3_step(update) == SQLITE_DONE)
{
NSLog(@"已经写入数据");
}
sqlite3_finalize(update);
}
}
else
{
NSLog(@"文件不存在");
}
下面代码从数据库中读取图片二进制数据,然后显示图片:
const char * sequel = "select image from test_table where name=?";
sqlite3_stmt * getimg;
if (sqlite3_prepare_v2(database, sequel, -1, &getimg, NULL) == SQLITE_OK)
{
char *name = "test";
sqlite3_bind_text(update, 1, name, -1, NULL);
if(sqlite3_step(getimg) == SQLITE_ROW)
{
int bytes = sqlite3_column_bytes(getimg, 0);
Byte * value = (Byte*)sqlite3_column_blob(getimg, 1);
if (bytes !=0 && value != NULL)
{
NSData * data = [NSData dataWithBytes:value length:bytes];
UIImage * img = [UIImage imageWithData:data];
UIImageView * aview =[[UIImageView alloc] initWithFrame:CGRectMake(0.0, 0.0, IMAGE_WIDTH, IMAGE_HEIGHT)];
aview.image = img;
[self.view addSubview:aview];
[aview release];
}
}
sqlite3_finalize(getimg);
}
转:http://blog.csdn.net/moliyll/article/details/7953656
参考:http://wiki.eoe.cn/page/iOS_blog_page_96451.html