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  • Hdu1540Tunnel Warfare线段树

      直接搞吧,就是用栈存复原点时要判下栈顶指针是否空。不然会wa在Hdu上。ps:打日本鬼子的题,必须ac啊

    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <climits>
    #include <string>
    #include <iostream>
    #include <map>
    #include <cstdlib>
    #include <list>
    #include <set>
    #include <queue>
    #include <stack>
    #include<math.h>
    using namespace std;
    #define lson l,mid,rt<<1
    #define rson mid+1,r,rt<<1|1
    const int maxn = 55555;
    int sum[maxn << 2];
    int lsum[maxn << 2];
    int rsum[maxn << 2];
    void up(int rt, int m)
    {
        lsum[rt] = lsum[rt << 1];
        rsum[rt] = rsum[rt << 1 | 1];
        if (lsum[rt] == (m - (m >> 1))) lsum[rt] += lsum[rt << 1 | 1];
        if (rsum[rt] == (m >> 1)) rsum[rt] += rsum[rt << 1];
        sum[rt] = max(max(sum[rt << 1], sum[rt << 1 | 1]), rsum[rt << 1] + lsum[rt << 1 | 1]);
    }
    
    void build(int l, int r, int rt)
    {
        if (l == r){
            sum[rt] = lsum[rt] = rsum[rt] = 1;
            return;
        }
        int mid = (l + r) >> 1;
        build(lson);
        build(rson);
        up(rt, r - l + 1);
    }
    
    void update(int key, int add, int l, int r, int rt)
    {
        if (l == r){
            if (add) sum[rt] = lsum[rt] = rsum[rt] = 0;
            if (!add) sum[rt] = lsum[rt] = rsum[rt] = 1;
            return;
        }
        int mid = (l + r) >> 1;
        if (key <= mid) update(key, add, lson);
        else update(key, add, rson);
        up(rt, r - l + 1);
    }
    
    int ask(int key, int l, int r, int rt)
    {
        if (l == r){
            if (sum[rt] == 1) return 1; return 0;
        }
        int mid = (l + r) >> 1;
        int a = l + lsum[rt] - 1; int b = r - rsum[rt] + 1;
        int ans = 0;
        if (key >= l&&key <= a) ans = lsum[rt];
        if (key >= b&&key <= r) ans = max(ans, rsum[rt]);
        int c = mid - rsum[rt << 1] + 1; int d = lsum[rt << 1 | 1] + mid;
        if (key >= c&&key <= d) ans = max(ans, rsum[rt << 1] + lsum[rt << 1 | 1]);
        if (ans) return ans;
        if (key <= mid) return ask(key, lson);
        else return ask(key, rson);
    }
    int q[maxn<<1];
    int main()
    {
        int n, m;
        int a; char str[100];
        while (scanf("%d%d",&n,&m)!=EOF){
            build(1, n, 1);
            int ans = 0;
            for (int i = 0; i < m; i++){
                scanf("%s%d", str, &a);
                if (str[0] == 'D'){
                    update(a, 1, 1, n, 1);
                    q[ans++] = a;
                }
                if (str[0] == 'Q'){
                    printf("%d
    ", ask(a, 1, n, 1));
                }
                if (str[0] == 'R'){
                    if(ans<=0) continue;
                    int t = q[--ans];
                    update(t, 0, 1, n, 1);
                }
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/yigexigua/p/3928295.html
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