题目描述
输入一个整数数组,判断该数组是不是某二叉搜索树的后序遍历的结果。如果是则输出Yes,否则输出No。假设输入的数组的任意两个数字都互不相同。
public boolean VerifySquenceOfBST(int[] sequence) { if (sequence == null || sequence.length == 0) return false; return verify(sequence, 0, sequence.length - 1); } private boolean verify(int[] sequence, int first, int last) { if (last - first <= 1) return true; int rootVal = sequence[last]; int cutIndex = first; while (cutIndex < last && sequence[cutIndex] <= rootVal) cutIndex++; for (int i = cutIndex; i < last; i++) if (sequence[i] < rootVal) return false; return verify(sequence, first, cutIndex - 1) && verify(sequence, cutIndex, last - 1); }