1、拥有自定义对象 MyUser
1 @Data 2 public class MyUser { 3 private String userName; 4 private String passWord; 5 }
2、编写自定义去重方法实现
/** * 根据list中对象某些字段去重 * @param list 需要去重的list * @return 返回去重后的list */ private static List<MyUser> removeDuplicateOutputField(List<MyUser> list) { Set<MyUser> set = new TreeSet<>(new Comparator<MyUser>() { @Override public int compare(MyUser myUser, MyUser myUserNew) { int compareToResult = 1;//==0表示重复 if(StringUtils.equals(myUser.getUserName(), myUserNew.getUserName()) && StringUtils.equals(myUser.getPassWord(), myUserNew.getPassWord())) { compareToResult = 0; } return compareToResult; } }); set.addAll(list); return new ArrayList<>(set); }
注意:其中StringUtils.equals() 传入两个比较对象对应的字段,
比如想要加入userName 字段去重 就要加入 如下条件即可, 想要添加几个字段自行添加即可
StringUtils.equals(myUser.getUserName(), myUserNew.getUserName()) 也可以 使用
myUser.getAge().equals(myUserNew.getAge()) 自行测试决定
3、测试结果
@Test public void distinctMyUser(){ List<MyUser> list1 = new ArrayList<>(); MyUser user1 = new MyUser(); user1.setUserName("zhangsan"); user1.setPassWord("1234567"); list1.add(user1); MyUser user2 = new MyUser(); user2.setUserName("zhangsan"); user2.setPassWord("123456"); list1.add(user2); MyUser user3 = new MyUser(); user3.setUserName("lisi"); user3.setPassWord("123456"); list1.add(user3); MyUser user4 = new MyUser(); user4.setUserName("lisi"); user4.setPassWord("123456"); list1.add(user4); for (MyUser b: list1) { System.out.println("去重前:"+b.toString()); } //去重 list1 = removeDuplicateOutputField(list1); for (MyUser b: list1) { System.out.println("去重后:"+b.toString()); } }
运行结果如下,达到预期,根据自己想要的字段进行list集合去重操作。
二、List<T> 自定义对象,根据某一列去重,利用lambad 来实现
@Test public void distinctList() { AdviceInfo adviceInfo = new AdviceInfo(); adviceInfo.setHospId(8888L); adviceInfo.setSex("女"); adviceInfo.setAge(22); AdviceInfo adviceInfo2 = new AdviceInfo(); adviceInfo2.setHospId(8888L); adviceInfo2.setSex("男"); adviceInfo2.setAge(22); ArrayList<AdviceInfo> adviceInfos = Lists.newArrayList(); adviceInfos.add(adviceInfo); adviceInfos.add(adviceInfo2); adviceInfos.stream().filter(distinctByKey(e -> e.getHospId())) .collect(Collectors.toList()) .forEach(adviceInfo1 -> System.out.println(adviceInfo1.getSex())); } public static <T> Predicate<T> distinctByKey(Function<? super T, Object> keyExtractor) { Map<Object, Boolean> map = new ConcurrentHashMap<>(); return t -> map.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null; }
运行结果: