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  • LeetCode: Search in Rotated Sorted Array

    少数次过

     1 class Solution {
     2 public:
     3     int search(int A[], int n, int target) {
     4         // Start typing your C/C++ solution below
     5         // DO NOT write int main() function
     6         int left, right, mid;
     7         left = 0, right = n-1;
     8         while (left <= right) {
     9             mid = (left+right)/2;
    10             if (target < A[0] && A[mid] >= A[0]) {
    11                 left = mid + 1;
    12                 continue;
    13             }
    14             if (target >= A[0] && A[mid] < A[0]) {
    15                 right = mid - 1;
    16                 continue;
    17             }
    18             if (target < A[mid]) right = mid-1;
    19             else left = mid+1;
    20         }
    21         return target == A[(left+right)/2]? (left+right)/2 : -1;
    22     }
    23 };

     C#

     1 public class Solution {
     2     public int Search(int[] nums, int target) {
     3         int left = 0, right = nums.Length - 1;
     4         while (left <= right) {
     5             int mid = (left + right) / 2;
     6             if (target < nums[0] && nums[mid] >= nums[0]) {
     7                 left = mid + 1;
     8                 continue;
     9             }
    10             if (target >= nums[0] && nums[mid] < nums[0]) {
    11                 right = mid - 1;
    12                 continue;
    13             }
    14             if (target < nums[mid]) right = mid - 1;
    15             else left = mid + 1;
    16         }
    17         return target == nums[(left + right) / 2]? (left + right) / 2 : -1;
    18     }
    19 }
    View Code
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  • 原文地址:https://www.cnblogs.com/yingzhongwen/p/3033401.html
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