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  • Algorithm: bit manipulation

    1. 一个数的从右起第p1位和第p2位swap n位

     1 unsigned int swapBits(unsigned int x, unsigned int p1, unsigned int p2, unsigned int n) {
     2     unsigned int set1 = (x >> p1) & ((1 << n) - 1);
     3     unsigned int set2 = (x >> p2) & ((1 << n) - 1);
     4     unsigned int xored = set1 ^ set2; //same is 0, different is 1
     5     xored = (xored << p1) | (xored << p2);
     6     return x ^ xored;  //anybit ^ 0 = anybit, anybit ^ 1 = !anybit, so same no need to change, different need to be changed
     7 }
     8 
     9 int main()
    10 {
    11     cout << swapBits(28, 0, 3, 2) << endl;
    12     return 0;
    13 }

     2. Add two integer

    1 int Add(int x, int y) {
    2     while (y) {
    3         int carry = x & y;
    4         x = x ^ y;
    5         y = carry << 1;
    6        // cout << carry << " " << x << " " << y << endl;
    7     }
    8     return x;
    9 }

    3. min函数

    1 int minnum(int x, int y) {
    2     return y + ((x - y) & ((x - y) >> (sizeof(int) * 8 - 1)));
    3 }

    also can use division

    4. count bit set in an integer

    1 int countsetbits(int x) {
    2     int ans = 0;
    3     while(x) {
    4         x &= (x-1);
    5         ans++;
    6     }
    7     return ans;
    8 }
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  • 原文地址:https://www.cnblogs.com/yingzhongwen/p/3566127.html
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